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Lena [83]
3 years ago
12

What are the soultion(s) to the quadratic equation 40- x^2=0

Mathematics
1 answer:
SSSSS [86.1K]3 years ago
3 0

Step-by-step explanation:

40 - x^2 = 0...subtract 40

-x^2 = -40....multiply both sides by -1

x^2 = 40

x = (+ - ) sqrt 40

x = (+ - ) sqrt 4 * 10

x = (+ - ) 2 sqrt 10

x = 2 sqrt 10, and x = -2 sqrt 10

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Unit rate for 3 pizzas at 19.99 is 6.66

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3 years ago
pam is making fruit punch for a party using the ratio of 2 cups of club soda with 5 cups of juice. complete the table to show eq
inn [45]

Answer:

from left to right 4,20,25,20

Step-by-step explanation:

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3 years ago
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igor_vitrenko [27]
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5 0
3 years ago
"Rebecca walks 100 feet in a straight line. She then turns 20 degrees to her left and walks another 100 feet, and then turns 20
iragen [17]

Answer:

1,800 ft

Step-by-step explanation:

Rebecca will walk in the pattern of a regular polygon with 'n' sides and internal angles of 160 degrees (180 at a straight line - 20 degrees from each turn).

The equation that describes the internal angle of a regular polygon is:

A = \frac{(n-2)*180}{n}

For A = 160 degrees:

160n=(n-2)*180\\(180-160)n=360\\n=18\ sides

If each side is 100 ft long, the total distance that Rebecca has walked is:

d = 18*100\\d=1,800\ ft

She walked 1,800 ft.

5 0
3 years ago
Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the
Rama09 [41]

<em><u>Question:</u></em>

Britney throws an object straight up into the air with an initial velocity of 27 ft/s from a platform that is 10 ft above the ground. Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the object to hit the ground?

1s   2s   3s   4s

<em><u>Answer:</u></em>

It takes 2 seconds for object to hit the ground

<em><u>Solution:</u></em>

<em><u>The given equation is:</u></em>

h(t) = -16t^2 + v_0t+h_0

Initial velocity = 27 feet/sec

h_0 = 10\ feet

Therefore,

h(t) = -16t^2 +27t+10

At the point the object hits the ground, h(t) = 0

-16t^2 +27t+10 = 0\\\\16t^2-27t-10=0

Solve by quadratic formula,

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=16,\:b=-27,\:c=-10:\quad \\\\t=\frac{-\left(-27\right)\pm \sqrt{\left(-27\right)^2-4\cdot \:16\left(-10\right)}}{2\cdot \:16}\\\\t = \frac{27 \pm \sqrt{1369}}{32}\\\\t = \frac{27 \pm 37}{32}\\\\We\ have\ two\ solutions\\\\t = \frac{27+37}{32}\\\\t = \frac{64}{32}\\\\t = 2\\\\And\\\\t = \frac{27-37}{32}\\\\t = -0.3125

Ignore, negative value

Thus, it takes 2 seconds for object to hit the ground

7 0
3 years ago
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