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tatyana61 [14]
3 years ago
12

A parking garage charges a fixed amount of money for each hour that it is used.

Mathematics
1 answer:
insens350 [35]3 years ago
5 0
Ok what is the rest of the question
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Based on the graph, if Joe earned $400, how many hours did he work?
mote1985 [20]
About 45 to 46 hours
8 0
3 years ago
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Joe left the hospital at the same time as Eugene. They drove in opposite directions. Eugene drove at a speed of 70 km/h. After t
Gala2k [10]

If Joe and Eugene are travelling in opposite directions, their total distance is 360 km.

Eugene's speed = 70 km/hour

Let Joe's speed be = x

They each travel for 3 hours, so time = 3 hours

Distance = speed * time

360=70(3)+x(3)

360=210+3x

3x=150

x=50

Hence, Joe's speed is 50 km per hour.


4 0
3 years ago
Jason and his 3 brothers want to buy a gift fr their mother. they have $314 saved. each of them will save $17 a week until they
Alenkasestr [34]
With each of them saving $17 a week for 3 weeks, they will be able to save up $153 after three weeks. Adding this amount to the original amount they had will give them $467. Obviously, they will not have enough money to buy the gift they want for their mother. They will be short of $48. 
5 0
3 years ago
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50 points giveaway <3 brainliest if u need extraaa
Igoryamba

hey how are you today?

Step-by-step explanation:

4 0
3 years ago
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How would I solve this equation? I also would like the steps please.
bagirrra123 [75]

Answer:

The answer to your question is x = 23.36

Step-by-step explanation:

                                          \frac{1250}{1.04^{x} } = 500

Solve for x

                                          1250 = 500(1.04)^{x}

                                          \frac{1250}{500} = 1.04^{x}

Apply logarithms

                                          2.5 = 1.04^{x}

                                          log 2.5 = x log 1.04

                                         x = 0.398 / 0.017

                                        x = 23.36                                            

4 0
3 years ago
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