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2 years ago

A parking garage charges a fixed amount of money for each hour that it is used.

Mathematics

1 answer:

insens350 [35]2 years ago

5 0

Ok what is the rest of the question

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What is the vertex of the absolute value function defined by ƒ(x) = |x + 2| + 4?

Marrrta [24]

Answer:

C. (-2,4)

Step-by-step explanation:

We have been given a function $f(x)=|x+2|+4$ and we are asked to find the vertex of our absolute value function.

The rules for the translation of a function are as follows:

$f|x-h|=\text{Graph shifted to right by h units}$

$f|x+h|=\text{ Graph shifted to left by h units}$

$f|x|+h=\text{ Graph shifted upward by h units}$

$f|x|-h=\text{ Graph shifted down by h units}$

Upon comparing our absolute function with above transformations we can see that our function is shifted to two units right of the origin(0,0) so x coordinate of our absolute function will be -2.

Our function is shifted upward from origin by 4 units, therefore, y-coordinate of our absolute value function will be 4.

$f(x)=|x--2|+4$

Therefore, the vertex of our absolute value function will be on point (-2,4) and option C is the correct choice.

4 0

3 years ago

Read 2 more answers

What is the answer to thiss

lana [24]

Hi Student!

This question is fairly simple because it gives us an equation and they also give us a value for the variable that is within the equation and they tell us evaluate the expression. So let's plug in the values and solve.

Plug in the values

$m^2 + 5$

$(9)^2 + 5$

Factor out the exponent

$(9*9) + 5$

$81 + 5$

Combine

$86$

Therefore, the final answer that we would get when substituting m with 9 in the given equation is that we get 86.

5 0

1 year ago

A certain geneticist is interested in the proportion of males and females in the population who have a minor blood disorder. In

lord [1]

Answer:

95% confidence interval for the difference between the proportions of males and females who have the blood disorder is [-0.064 , 0.014].

Step-by-step explanation:

We are given that a certain geneticist is interested in the proportion of males and females in the population who have a minor blood disorder.

A random sample of 1000 males, 250 are found to be afflicted, whereas 275 of 1000 females tested appear to have the disorder.

Firstly, the pivotal quantity for 95% confidence interval for the difference between population proportion is given by;

P.Q. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of males having blood disorder= $\frac{250}{1000}$ = 0.25

$\hat p_2$ = sample proportion of females having blood disorder = $\frac{275}{1000}$ = 0.275

$n_1$ = sample of males = 1000

$n_2$ = sample of females = 1000

$p_1$ = population proportion of males having blood disorder

$p_2$ = population proportion of females having blood disorder

Here for constructing 95% confidence interval we have used Two-sample z proportion statistics.

So, 95% confidence interval for the difference between the population proportions, ( $p_1-p_2$ ) is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level

of significance are -1.96 & 1.96}

P(-1.96 < $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ < ${(\hat p_1-\hat p_2)-(p_1-p_2)}$ < $1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ ) = 0.95

P( $(\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ < ( $p_1-p_2$ ) < $(\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ ) = 0.95

95% confidence interval for ( $p_1-p_2$ ) =

[ $(\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ , $(\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ ]

= [ $(0.25-0.275)-1.96 \times {\sqrt{\frac{0.25(1-0.25)}{1000}+ \frac{0.275(1-0.275)}{1000}} }$ , $(0.25-0.275)+1.96 \times {\sqrt{\frac{0.25(1-0.25)}{1000}+ \frac{0.275(1-0.275)}{1000}} }$ ]

= [-0.064 , 0.014]

Therefore, 95% confidence interval for the difference between the proportions of males and females who have the blood disorder is [-0.064 , 0.014].

8 0

3 years ago

Can anyone help me???

Alenkinab [10]

Answer: think A

Step-by-step explanation:

3 0

2 years ago

Find the y intercept. I already found the slope is 9.

jeka57 [31]

The slope-intercept form: y = mx + b

We have the slope m = 9, therefore: y = 9x + b.

Next. We have the table:

x | -5 | -2 | 1 | 3 | 4 |

y |-46|-19| 8 |26|35|

(1, 8) → x = 1, y = 8

substitute the values of x and y to the equation:

8 = 9(1) + b

8 = 9 + b |-9

b = -1

Answer: y = 9x - 1 → y-intercept is -1.

8 0

3 years ago