24.6(x+5)=6x+30
25.-8(y-1)=-8y+8
26.-3(-5z+12)=15z-36
27.1/3(6z+10)=2z+10/3
First, we are going to find if the function is odd or even. Remember that we can determine if a function is odd of even from its graph by looking at its ends; if both ends go to the same the direction, the function is even. If both ends go to opposite directions, the function is odd. At both ends, the graph of our function go towards the same direction, minus infinity, so we can conclude that our function is even.
Next, we are going to find the possible degree of our function. Remember that the possible degree of a function is the number of x-intercepts.
We can infer from our graph that the function intercepts the x-axis at least 6 times.
We can conclude that the correct answer is: even degrees of 6 or greater.
Answer:
279+1.80s
Step-by-step explanation:
If we add the material cost to the labor cost, this would give us the manufacturing cost.
M(s)+L(s)=(225+0.65s)+(54+1.15s)
We will not combine like terms.
(M+L)s=225+54+0.65s+1.15s
Simplify.
(M+L)s=279+1.80s
Answer:
C = 5.
Step-by-step explanation:
First, you need to remember that:
For the function:
h(x) = Sinh(k*x)
We have:
h'(x) = k*Cosh(k*x)
and for the Cosh function:
g(x) = Cosh(k*x)
g'(x) = k*Cosh(k*x).
Now let's go to our problem:
We have f(x) = A*cosh(C*x) + B*Sinh(C*x)
We want to find the value of C such that:
f''(x) = 25*f(x)
So let's derive f(x):
f'(x) = A*C*Sinh(C*x) + B*C*Cosh(C*x)
and again:
f''(x) = A*C*C*Cosh(C*x) + B*C*C*Sinh(C*x)
f''(x) = C^2*(A*cosh(C*x) + B*Sinh(C*x)) = C^2*f(x)
And we wanted to get:
f''(x) = 25*f(x) = C^2*f(x)
then:
25 = C^2
√25 = C
And because we know that C > 0, we take the positive solution of the square root, then:
C = 5
If every minute 3 poles past and poles are 1/4 mile (0.25 mile) apart;
3x0.25 = 0.75
Train moves 0.75 mile/per minute
If you want the train's speed per hour, then;
x = 60x0.75
x= 45miles per hour is the speed of the train