a. What percent of people earn less than $40000?
Solution: Let S be the random variable of a salary of employee (in $), S ~ N(50000,20000). Then the random
variable X =−50000
20000
~N(0,1).
( < 40000) = ( <
40000 − 50000
20000 ) = ( < −0.5) = (−0.5) = 0.3085375.
Here Φ(x) denotes the cumulative distribution function of a standard normal distribution.
Answer: 31%.
b. What percent of people earn between $45000 and $65000?
Solution:
(45000 < < 65000) = (
45000 − 50000
20000 < <
65000 − 50000
20000 ) = (−0.25 < < 0.75)
= (0.75) − (−0.25) = 0.7733726 − 0.4012937 = 0.3720789.
Answer: 37%.
c. What percent of people earn more than $70000?
Solution:
( > 70000) = ( >
70000 − 50000
20000 ) = ( > 1) = 0.8413447.
Answer: 84%.
Y = mx + b
slope(m) = -4
(-2,5)....x = -2 and y = 5
now we sub into the formula and find b, the y int
5 = -4(-2) + b
5 = 8 + b
5 - 8 = b
-3 = b
so ur equation is : y = -4x - 3 <==
Answer:
y = 2/3x+1/3
Step-by-step explanation:
2x−3y+1 = 0
Solve for y
Add 3y to each side
2x−3y+1 +3y= 0+3y
2x +1 = 3y
Divide by 3
2/3 x + 1/3 =3y/3
2/3x +1/3 = y
The slope is 2/3 and the y intercept is 1/3
y = 2/3x+1/3
Answer:
C
Step-by-step explanation:
Answer:
( 2 - x )^2
Step-by-step explanation:
