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neonofarm [45]
3 years ago
11

Give an example of a 2x2 matrix without any real eigenvalues:___________

Mathematics
1 answer:
9966 [12]3 years ago
3 0

Answer:

Step-by-step explanation:

An eigenvalue of n × n is a function of a scalar \lambda  considering that there is a solution (i.e. nontrivial) to an eigenvector x of Ax =  

Suppose the matrix A = \left[\begin{array}{cc}-1&-1\\2&1\\ \end{array}\right]

Thus, the equation of the determinant (A - \lambda1) = 0

This implies that:

\left[\begin{array}{cc}-1-\lambda &-1\\2&1- \lambda\\ \end{array}\right] =0

-(1 - \lambda^2 ) + 2 = 0

-1 + \lambda ^2 + 2= 0

\lambda^2 +1 =0

Hence, the eigenvalues of the equation are \mathtt{\lambda = i , -i}

Also, the eigenvalues can be said to be complex numbers.

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Answer:

Hence, none of the options presented are valid. The plane is represented by 3 \cdot x + 3\cdot y + 2\cdot z = 6.

Step-by-step explanation:

The general equation in rectangular form for a 3-dimension plane is represented by:

a\cdot x + b\cdot y + c\cdot z = d

Where:

x, y, z - Orthogonal inputs.

a, b, c, d - Plane constants.

The plane presented in the figure contains the following three points: (2, 0, 0),  (0, 2, 0), (0, 0, 3)

For the determination of the resultant equation, three equations of line in three distinct planes orthogonal to each other. That is, expressions for the xy, yz and xz-planes with the resource of the general equation of the line:

xy-plane (2, 0, 0) and (0, 2, 0)

y = m\cdot x + b

m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

Where:

m - Slope, dimensionless.

x_{1}, x_{2} - Initial and final values for the independent variable, dimensionless.

y_{1}, y_{2} - Initial and final values for the dependent variable, dimensionless.

b - x-Intercept, dimensionless.

If x_{1} = 2, y_{1} = 0, x_{2} = 0 and y_{2} = 2, then:

Slope

m = \frac{2-0}{0-2}

m = -1

x-Intercept

b = y_{1} - m\cdot x_{1}

b = 0 -(-1)\cdot (2)

b = 2

The equation of the line in the xy-plane is y = -x+2 or x + y = 2, which is equivalent to 3\cdot x + 3\cdot y = 6.

yz-plane (0, 2, 0) and (0, 0, 3)

z = m\cdot y + b

m = \frac{z_{2}-z_{1}}{y_{2}-y_{1}}

Where:

m - Slope, dimensionless.

y_{1}, y_{2} - Initial and final values for the independent variable, dimensionless.

z_{1}, z_{2} - Initial and final values for the dependent variable, dimensionless.

b - y-Intercept, dimensionless.

If y_{1} = 2, z_{1} = 0, y_{2} = 0 and z_{2} = 3, then:

Slope

m = \frac{3-0}{0-2}

m = -\frac{3}{2}

y-Intercept

b = z_{1} - m\cdot y_{1}

b = 0 -\left(-\frac{3}{2} \right)\cdot (2)

b = 3

The equation of the line in the yz-plane is z = -\frac{3}{2}\cdot y+3 or 3\cdot y + 2\cdot z = 6.

xz-plane (2, 0, 0) and (0, 0, 3)

z = m\cdot x + b

m = \frac{z_{2}-z_{1}}{x_{2}-x_{1}}

Where:

m - Slope, dimensionless.

x_{1}, x_{2} - Initial and final values for the independent variable, dimensionless.

z_{1}, z_{2} - Initial and final values for the dependent variable, dimensionless.

b - z-Intercept, dimensionless.

If x_{1} = 2, z_{1} = 0, x_{2} = 0 and z_{2} = 3, then:

Slope

m = \frac{3-0}{0-2}

m = -\frac{3}{2}

x-Intercept

b = z_{1} - m\cdot x_{1}

b = 0 -\left(-\frac{3}{2} \right)\cdot (2)

b = 3

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After comparing each equation of the line to the definition of the equation of the plane, the following coefficients are obtained:

a = 3, b = 3, c = 2, d = 6

Hence, none of the options presented are valid. The plane is represented by 3 \cdot x + 3\cdot y + 2\cdot z = 6.

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