The derivative of 1/logx is With the chain rule.
1log(x)=log(x)−1 is ,= -1xlog(x)2 .
The by-product of logₐ x (log x with base a) is 1/(x ln a). Here, the thrilling issue is that we have "ln" withinside the by-product of "log x". Note that "ln" is referred to as the logarithm (or) it's miles a logarithm with base "e".
The by-product of 1/log x is -1/x(log x)^2. Note that 1/logx is the reciprocal of log.

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Answer:
I guess this is the answer
Height is 18 for question 3.
8(v−4)+7v=−2
(8)(v)+(8)(−4)+7v=−2
8v+−32+7v=−2
(8v+7v)+(−32)=−2
15v+−32=−2
15v−32=−2
Add 32 to both sides.
15v−32+32=−2+32
15v=30
Divide both sides by 15.
15v/15=30/15
v = 2
<span>8 ≥ 16y
Divide both sides by 16.
0.5 </span>≥ y, or y ≤ 0.5.
The answer is A) y ≤ 0.5.