All categories

3 years ago

How does the Pythagorean theorem work?

Mathematics

2 answers:

telo118 [61]3 years ago

8 0

A2 +b2=c2 is the answer for this question

zzz [600]3 years ago

7 0

Answer:

If you have a right angled triangle, the longer side (hypotenuse, opposite the right angle) be c length, the other shorter sides be a and b length

A squared x B squared = C squared

You might be interested in

Idk a? or no? like im really bad

kozerog [31]

Answer:

Step-by-step explanation:

0.0125

so it is 1.25 because the thousand place onward, it is in the decimal place of the percent

6 0

3 years ago

C•C (c=4) evaluating expressions

bearhunter [10]

Answer:

Step-by-step explanation:

if c = 4, then

(c)(c) = 16

if I misinterpreted your equation, please tell me.

5 0

2 years ago

Alex is trying to run a certain number of miles by the end of the month Alex is 40% of the way to achieving her goal and she alr

docker41 [41]

Answer:

30 miles

Step-by-step explanation:

Given that:

Alex has some target to run a certain number of miles by the end of the month.

Goal already achieved = 40% of the total goal

Number of miles already run by Alex = 12 miles

To find:

Number of miles that Alex is trying to run by the end of month?

Solution:

We have to find nothing but the goal of Alex here.

Let the number of miles that Alex is trying to run by the end of the month = $x$ miles

As per question statement:

40% of total number of miles to be run = 12 miles

$\dfrac{40}{100}\times x = 12\\\Rightarrow 40x=12\times 100\\\Rightarrow x = \dfrac{1200}{40}\\\Rightarrow \bold{x = 30\ miles}$

Total number of miles that Alex is trying to run by the end of the month = <em>30 miles</em>

4 0

3 years ago

Choose the expression that is equivalent to 12p2-2/5(5p2-10)+3p

Margarita [4]

Answer:

$10p^2+3p+4$

Step-by-step explanation:

$12p^2-\frac{2}{5} (5p^2-10)+3p\\12p^2-0.4 (5p^2-10)+3p\\12p^2-2p^2+4+3p\\10p^2+3p+44$

8 0

3 years ago

Pls help because I’m not sure

leva [86]

Step-by-step explanation:

8 0

2 years ago