Ask question

Ask question

All categories

3 years ago

10

What is the value of the function when x = −2, y =?

1 answer:

shtirl [24]3 years ago

3 0

As you can see on the graph, when x=-2, y=-3.

You might be interested in

Find the vectors T, N, and B at the given point. r(t) = < t^2, 2/3t^3, t >, (1, 2/3 ,1)

maxonik [38]

Answer with Step-by-step explanation:

We are given that

$r(t)=< t^2,\frac{2}{3}t^3,t >$

We have to find T,N and B at the given point t > (1, $2/3$ ,1)

$r'(t)=$

$\mid r'(t) \mid=\sqrt{(2t)^2+(2t^2)^2+1}=\sqrt{(2t^2+1)^2}=2t^2+1$

$T(t)=\frac{r'(t)}{\mid r'(t)\mid}=\frac{}{2t^2+1}$

Now, substitute t=1

$T(1)=\frac{}{2+1}=\frac{1}{3}$

$T'(t)=\frac{-4t}{(2t^2+1)^2} +\frac{1}{2t^2+1}$

$T'(1)=-\frac{4}{9}+\frac{1}{3}$

$T'(1)=\frac{1}{9}=$

$\mid T'(1)\mid=\sqrt{(\frac{-2}{9})^2+(\frac{4}{9})^2+(\frac{-4}{9})^2}=\sqrt{\frac{36}{81}}=\frac{2}{3}$

$N(1)=\frac{T'(1)}{\mid T'(1)\mid}$

$N(1)=\frac{}{\frac{2}{3}}=$

$N(1)=$

$B(1)=T(1)\times N(1)$

$B(1)=\begin{vmatrix}i&j&k\\\frac{2}{3}&\frac{2}{3}&\frac{1}{3}\\\frac{-1}{3}&\frac{2}{3}&\frac{-2}{3}\end{vmatrix}$

$B(1)=i(\frac{-4}{9}-\frac{2}{9})-j(\frac{-4}{9}+\frac{1}{3})+k(\frac{4}{9}+\frac{2}{9})$

$B(1)=-\frac{2}{3}i+\frac{1}{3}j+\frac{2}{3}k$

$B(1)=\frac{1}{3}$

5 0

3 years ago

What is the sum of 3.6 x 10^3 and 6.1 x 10^3?

g100num [7]

9.7 x 10^3

It is the same as 3600 + 6100 = 9700 => 9.7 X 10^3

7 0

3 years ago

Read 2 more answers

Solve for x. x -5 x 7 ÷(8 - 9)<br> help lease

Colt1911 [192]

The answer is 35 !!!!!!!!!!!!!

6 0

3 years ago

Read 2 more answers

If f(x)=x-2 which of the following is the inverse of f(x) brainly

Lostsunrise [7]

Answer:

The inverse of f(x) is $f ^ {- 1}(x) = x + 2$

Step-by-step explanation:

To find the inverse of the function $f (x) = x-2$ , perform the following steps:

1) do $y = f (x)$

$y = x-2$

2) Solve the equation for the variable x.

$y + 2 = x -2 +2$

$y + 2 = x$

3) exchange the variable x with the variable y

$y + 2 = x$ ----> $x + 2 = y$

4) Change the variable y by $f ^{- 1}(x)$

Finally the inverse function is:

$f ^ {- 1} (x) = x + 2$

4 0

3 years ago

(3 x 10-8exopet -8<br> )(3 x 10exponet9)

valina [46]

Answer:

=66.501505not9x21−1310.355601no2pt10x12−177.337346not9x11

Step-by-step explanation:

8 0

3 years ago