3y + 3y + 4 = 4
Convert to the form ax = b
3y + 3y = 4 - 4
6y = 0
y = 0
<h2>One solution</h2>
Let first number =a
Let second number = b
a =b+ 19
:b+b+19=43
2b+19=43
2b=43-19
2b=24
b=24/2
b=12
a=b+19
=12+19
=31
Check:31+12
=43
Answer:
![\large\boxed{A:B:C=\dfrac{1}{10A}}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7BA%3AB%3AC%3D%5Cdfrac%7B1%7D%7B10A%7D%7D)
Step-by-step explanation:
![A=\dfrac{B}{2}=\dfrac{C}{5}\\\\A=\dfrac{B}{2}\qquad\text{multiply both sides by 2}\\\\2A=B\to\boxed{B=2A}\\\\A=\dfrac{C}{5}\qquad\text{multiply both sides by 5}\\\\5A=C\to C=5A\\\\A:B:C=A:2A:5A=1:2:5A=\dfrac{1}{2}:5A=\dfrac{1}{2}\cdot\dfrac{1}{5A}=\dfrac{1}{10A}](https://tex.z-dn.net/?f=A%3D%5Cdfrac%7BB%7D%7B2%7D%3D%5Cdfrac%7BC%7D%7B5%7D%5C%5C%5C%5CA%3D%5Cdfrac%7BB%7D%7B2%7D%5Cqquad%5Ctext%7Bmultiply%20both%20sides%20by%202%7D%5C%5C%5C%5C2A%3DB%5Cto%5Cboxed%7BB%3D2A%7D%5C%5C%5C%5CA%3D%5Cdfrac%7BC%7D%7B5%7D%5Cqquad%5Ctext%7Bmultiply%20both%20sides%20by%205%7D%5C%5C%5C%5C5A%3DC%5Cto%20C%3D5A%5C%5C%5C%5CA%3AB%3AC%3DA%3A2A%3A5A%3D1%3A2%3A5A%3D%5Cdfrac%7B1%7D%7B2%7D%3A5A%3D%5Cdfrac%7B1%7D%7B2%7D%5Ccdot%5Cdfrac%7B1%7D%7B5A%7D%3D%5Cdfrac%7B1%7D%7B10A%7D)
3x-4 +15-x+3x+6 =32
Does that help?