Answer:
width =19 inches
length= 27 inches
Step-by-step explanation:
Let width be w inches so according to given scenario as length is 8 more than width so the equation becomes
l=8+w inches (Equation 1)
Area of Rectangle= L*w
Area= 513
L*w=513 (Equation 2)
Putting l's value from equation 1 in equation 2
(8+w)w=513
w^2+8w-513=0
Making Factors
w^2+27w-19w-513=0
w(w+27)-19(w+27)=0
(w-19)(w+27)=0
w=19, w=-27
as width cannot be negative so if we only consider w=19 then
l=8+19
l=27
You should get the answer 154 afte u subtract and at that school be your answer
Answer:
Square root of 4 is 2
so 1+![\frac{[1+\sqrt{2x-1]}^2 }{4}](https://tex.z-dn.net/?f=%5Cfrac%7B%5B1%2B%5Csqrt%7B2x-1%5D%7D%5E2%20%7D%7B4%7D)
=4
frac{[1+sqrt{2x-1]}^2 }{4}=3
so 1+sqrt{2x-1]}^2=12
so 1+sqrt{2x-1}=V12
sqrt{2x-1}=V12-1
2x-1=(V12-1)^2=12-2V12+1=13-2V12
2x=13+1-2V12
2x=14-2V12
x=7-V12
x=7-2V3
I put an attachment to explain better
Step-by-step explanation:
