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natima [27]
3 years ago
7

Eliminate 3x+2y=4 8x-3y=-6

Mathematics
1 answer:
laila [671]3 years ago
7 0
Steps:
1. Multiply the first line by 3 and the second by 2
3(3x + 2y= 4)
2(8x -3y=-6)
2. New lines are
9x + 6y= 12
16x + -6y=-12
3. Now add/subtract them
25x + 0= 0
25x=0
4. Divide by 25
X=0

5. To find y, substitute the 0 in the x in one of the equations
9x + 6y= 12
9(0) + 6y= 12
6y= 12
6. Divide by 6, your Y=2
7. X=0, Y=2
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2x - 4 = -8 what is the value of x?
Brums [2.3K]

Answer:

x = -2

Step-by-step explanation:

2x = -8+4

2x = -4

x = -2

CHECK

-4 - 4 = -8

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What is the solution to the inequality?
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7x + 18 > -3

Subtract 18 from both sides, 
7x > -21

Divide from 7, 
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In short, Your Answer would be Option D

Hope this helps!
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2 years ago
Evaluate each expression for the given value of the variables. 2x + y for x= 7 and y = 11​
prisoha [69]

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25

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2 years ago
A contractor developed a multiplicative time-series model to forecast the number of contracts in future quarters, using quarterl
dusya [7]

There is a missing content in the question.

After the statements and before the the options given; there is an omitted content which says:

Referring to Table 16-5, in testing the coefficient of X in the regression equation (0.117) the results were a t-statistic of 9.08 and an associated p-value of 0.0000. Which of the following is the best interpretation of this result?

Answer:

C. The quarterly growth rate in the number of contracts is significantly different from 0% (? = 0.05).

Step-by-step explanation:

From the given question:

The resulting regression equation can be represented as:

\hat Y = 3.37 + 0.117 X - 0.083 Q_1 + 1.28 Q_2 + 0.617Q_3

where;

the estimated number of contracts in a quarter X is the coded quarterly value with X = 0

the first quarter of 2010 Q1 is a dummy variable equal to 1 in the first quarter of a year and 0 otherwise

Q2 is a dummy variable equal to 1 in the second quarter of a year and 0 otherwise

Q3 is a dummy variable equal to 1 in the third quarter of a year and 0 otherwise

Our null and alternative hypothesis can be stated as;

Null hypothesis :

H_0 :  The quarterly growth rate in the number of contracts is not  significantly different from 0% (? = 0.05)

H_a:  The quarterly growth rate in the number of contracts is significantly different from 0% (? = 0.05)

The decision rule is to reject the null hypothesis if the p-value is less than 0.05.

From the missing omitted part we added above; we can see that the   t-statistics value = 9.08 and the p-value = 0.000 .

Conclusion:

Thus; we reject the null hypothesis and accept the alternative hypothesis. i.e

The quarterly growth rate in the number of contracts is significantly different from 0% (? = 0.05)

4 0
3 years ago
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