Eliminate 3x+2y=4 8x-3y=-6

1 answer:

7 0

Steps:
1. Multiply the first line by 3 and the second by 2
3(3x + 2y= 4)
2(8x -3y=-6)
2. New lines are
9x + 6y= 12
16x + -6y=-12
3. Now add/subtract them
25x + 0= 0
25x=0
4. Divide by 25
X=0

5. To find y, substitute the 0 in the x in one of the equations
9x + 6y= 12
9(0) + 6y= 12
6y= 12
6. Divide by 6, your Y=2
7. X=0, Y=2

You might be interested in

Evaluate the expression when c=21 and d=4. c-5d

vekshin1

$\huge \boxed{\mathfrak{Question} \downarrow}$

Evaluate the expression when c = 21 and d = 4, c - 5d = ?

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

Given,

c = 21
d = 4
c - 5d = ?

Let's solve it now :-

$\sf \: c - 5d \\ \\ \sf \: Substitute \: the \: values \: of \: c \: and \: d \\ \\ \sf c - 5d \\ \rightarrow \sf(21) - 5(4) \\ \sf \rightarrow21 - 20 \\ = \boxed{\boxed{\bf \: 1}}$

The value of the expression is 1.

6 0

3 years ago

What improper fraction can be written as a whole number. 10/6 12\6 14\6 16\6?

Burka [1]

12/6 can be written as 2 because 6 can go into 12 two times.

7 0

4 years ago

A candy store makes a 13–pound mixture of gummy bears, jelly beans, and gobstoppers. The cost of gummy bears is $1.00 per pound,

bulgar [2K]

X = gummy bears, y = jelly beans, z = gobstoppers
x + y + z = 13
x + 2y + 2z = 20
x = 3y

3y + y + z = 13
4y + z = 13

3y + 2y + 2z = 20
5y + 2z = 20

4y + z = 13....multiply by -2
5y + 2z = 20
-----------------
-8y - 2z = -26
5y + 2z = 20
---------------add
-3y = -6
y = 2........2 lbs jelly beans

x = 3y
x = 3(2)
x = 6....6 lbs gummy bears

x + y + z = 13
6 + 2 + z = 13
8 + z = 13
z = 13 - 8
z = 5........5 lbs gobstoppers

so we have : 6 lbs gummy bears (x), 2 lbs jelly beans (y), and 5 lbs gobstoppers (z)

5 0

3 years ago

Read 2 more answers

HELP ME I NEED HELLLPPP I AM A 6th grater if u ask HELLLPP ME

Ulleksa [173]

Answer:

Multiply by 3;9

Step-by-step explanation:

9/3=3

12/4=3

18/6=3

27/n=3