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3 years ago

Complete the table of ordered pairs for the given linear equation

Mathematics

1 answer:

nika2105 [10]3 years ago

4 0

Answer:

First blank= -1

Second blank= 14

Step-by-step explanation:

Plug in x to the equation. 1/7 x (-7)= -7/7=-1

2=1/7(x) to divide fractions you multiply by the reciprocal

2 x 7/1= 1/7× 7/1

14/1=14

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Find the derivative of 3e^y+x=y

Sindrei [870]

You have the following function:

$y=3e^y+x$

Derivate implictly the previous expression, as follow:

$y^{\prime}=3e^yy^{\prime}+1$

Where you have used that:

$(e^y)^{\prime}=e^yy^{\prime}$

Then, the implicit derivative of the given expression is:

$y^{\prime}=3e^yy^{\prime}+1$

Next, solve for y' as follow:

$\begin{gathered} y^{\prime}-3e^yy^{\prime}=1 \\ (1-3e^y)y^{\prime}=1 \\ y^{\prime}=\frac{1}{1-3e^y} \end{gathered}$

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1 year ago

In 15 and 16, use the expression 1 + z/3 + 2w

stiks02 [169]

Dang I’m dumb byeee use photo math it’s a app

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3 years ago

The following options are available for a car wash

Margaret [11]

Answer:

£576

(would really, reallly appreciate the brainliest)

Step-by-step explanation:

8 * 60 * 3/5 + 12 * 60 * 2/5

3 0

3 years ago

The perimeter of an equilateral triangle is p and the length of a side is s.

kompoz [17]

Answer:

s=7

p=3s

Step-by-step explanation:

The perimeter is the side length times 3

So the equation would be p=3s

Plug in 21 for p

21=3s

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2 years ago

Find the roots of:

Elena-2011 [213]

$\large\displaystyle\text{$\begin{gathered}\sf \pmb{1) \ 2x^3-7x^2+8x-3=0 } \end{gathered}$}$

Synthetic division is used since the equation is of the third degree. The divisors of -3 are 1, -1, 3, +3. So:

| 2 -7 8 -3

1 | 2 -5 3

| 2 -5 3 0

1 | 2 -3

2 -3 0

So the factorization is (x-1)² (2x-3)=0. So:

$\bf{ x_1=x_2=1 \qquad x_2=\dfrac{3}{2} }$

$\large\displaystyle\text{$\begin{gathered}\sf \pmb{2) \ x^3-x^2-4=0 } \end{gathered}$}$

Synthetic division is used since the equation is of the third degree. The divisors of -4 are 1, -1, 2, -2, 4, -4. So:

| 1 -1 0 -4

2 | 2 2

1 2 2 0

So the factorization is (x-2)(x²+x+2)=0 . When calculating the discriminant of the trinomial, it is concluded that it has no roots since the result is negative. So you only have one solution.

$\bf{ 1^2-4(2)(2)=1-16=-15 < 0 \quad \Longrightarrow \quad x=2 }$

$\large\displaystyle\text{$\begin{gathered}\sf \pmb{3) \ 6x^3+7x^2-9x+2=0 } \end{gathered}$}$

Synthetic division is used since the equation is of the third degree. The divisors of 2 are 1, -1, 2, -2. So:

| 6 7 9 2

-2 | -12 10 -2

6 -5 1 0

So the factorization is (x+2)(6x²-5x+1)=0 . The quadratic equation is solved by the general formula:

$\bf{ x_{2, 3}&=\dfrac{5\pm \sqrt{(5)^2-4(6)(1)}}{2(6)}=\dfrac{5\pm \sqrt{25-24}}{12}=\dfrac{5\pm 1}{12} }}$

$\large\displaystyle\text{$\begin{gathered}\sf \begin{matrix} x_1=-2&\ \ \ \ \ \ x_{2}=\dfrac{6}{12} \qquad &\ \ \ x_3=\dfrac{4}{12}\\ &\ \ \ x_2=\dfrac{1}{2} \qquad &x_3=\dfrac{1}{3} \end{matrix} \end{gathered}$}$

6 0

2 years ago