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Levart [38]
3 years ago
8

For a proof by induction of the math statement below, identify the correct step for proving the theorem is true for n = k + 1. H

ELP ASAP THANKS!!

Mathematics
1 answer:
Pavel [41]3 years ago
4 0
<h3>Answer: Choice A</h3>

What we do is simply replace every n with k+1. So (3n)^2 turns into (3(k+1))^2

We see that only choice A has the correct term mentioned on the left hand side, so this must be the answer.

The right hand side is treated the same way. We plug in n = k+1. Your teacher did a bit of algebraic manipulation to get what is shown for choice A.

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$1.5 per shirt if that's what you meant

Step-by-step explanation:

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3 years ago
The graph below shows a system of equations: Draw a line labeled y equals x plus 4 by joining the ordered pairs negative 4, 0 an
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Convert standard form to slope<br><br> 6x+5y=-15
siniylev [52]

Answer:

Step-by-step explanation:

1. Isolate Y by subtracting 6x from both sides.

2. Divide everything by 5, since 5 is the coefficient of Y

Final equation:

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Hope this helps!

4 0
3 years ago
PLS HELP ASAP If -2 is added to each of the x and y intercepts of the line 3x + 2y = 6, find the new equation of the line
ella [17]

Answer:

3x + 2y = -4

Step-by-step explanation:

x intercept of the line occurs at y = 0

Given the equation 3x+2y = 6

3x+2(0) = 6

3x  = 6

x = 2

The x intercept is at (2, 0)

Adding -2 to each axis will give (2-2, 0-2) = (0, -2)

y intercept of the line occurs at x = 0

Given the equation 3x+2y = 6

3(0)+2y = 6

2y  = 6

y =3

The x intercept is at (0, 3)

Adding -2 to each axis will give (0-2, 3-2) = (-2, 1)

The new coordinates are (0, -2 and (-2, 1)

Using the point slope form of the equation y - y0 = m(x-x0)

slope m = y2-y1/x2-x1

m = 1-(-2)/-2-0

m = 1+2/-2

m = -3/2

Using m = -3/2 and (0, -2)

y - (-2) = -3/2(x-0)

y+2 = -3/2 x

2(y+2) = -3x

2y+4 = -3x

-3x-2y = 4

3x + 2y = -4

Hence the required equation is 3x + 2y = -4

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3 years ago
How many significant digits is in 70.00?
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Going by what I was taught in chemistry, there would only be 1.
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