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Anettt [7]
2 years ago
15

The length of a rectangle is

Mathematics
1 answer:
laiz [17]2 years ago
8 0

Answer:

20 inches long and 7 inches wide

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How many triangles can be constructed with sides measuring 6 cm, 2 cm, and 7 cm? more than one none one
serious [3.7K]

Answer:

None

Step-by-step explanation:

By using the equation a^2 +b^2=c^2 we can see if it will work.

Substitute a for 6 and b for 2 to get 6^2+2^2=40

when you \sqrt{40} you don't get 7 therefore you cant make any triangles

7 0
2 years ago
Dinner party limited to 10 guests. 15 friends are democrats, 10 are republican and 1 is independent. The guests are randomly sel
alexandr402 [8]
C i gess is the answer
8 0
3 years ago
Please help 7(-37 + k) = 26
Georgia [21]

Answer:

7(k−37)=26

  • Divide both sides by 7

k−37= 26/7

  • Add 37 to both sides

k= 26/7 +37

  • Simplify  26/7 +37 to 285/7

k= 285/7

Decimal Form: 40.714286

​

3 0
2 years ago
Read 2 more answers
What is the greatest common factor of the two expressions?<br> 7a^2<br> 8a^3b^2
Andreyy89

Answer:

a²

Step-by-step explanation:

(see attached for reference)

We can find GCF by expressing each expression into their prime factors

7a² = 7 x a x a

8a³b² = 8 x a x a x a x b x b

by observation, we can see that a x a or a² shows up in both expressions, highlighted in bold here:

7a² = 7 x <em>a x a</em>

8a³b² = 8 x <em>a x a</em> x a x b x b

Hence the greatest common factor is a x a = a²

6 0
3 years ago
The Library is 1.75 miles directly north of the school the park is 0.6 miles directly south of the school.How far is the library
statuscvo [17]

Answer: 2.35 miles

Check out the attached image below. A drawing often helps visualize the problem. In this case, all three locations are along the same vertical line. The distances 1.75 and 0.6 can be added up as those smaller segments form the entire distance we want (from park to library). So that's how I got 1.75+0.6 = 2.35

5 0
2 years ago
Read 2 more answers
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