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3 years ago

The length of a rectangle is

Mathematics

1 answer:

laiz [17]3 years ago

8 0

Answer:

20 inches long and 7 inches wide

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Can anyone please help me step by step on how to solve this problem?

Sholpan [36]

Answer:

see explanation

Step-by-step explanation:

The volume (V) of a cuboid is calculated using the formula

V = lbh ( l is length, b is breadth and h is height )

Equate the product of the dimensions to 374

2(x + 3)(x + 9) = 374 ( divide both sides by 2 )

(x + 3)(x + 9) = 187 ← expand factors on left side

x² + 12x + 27 = 187 ( subtract 187 from both sides )

x² + 12x - 160 = 0 ← in standard form

Factor by considering the factors of the constant term (- 160) which sum to give the coefficient of the x- term (+ 12)

The factors are + 20 and - 8, hence

(x + 20)(x - 8) = 0

Equate each factor to zero and solve for x

x + 20 = 0 ⇒ x = - 20

x - 8 = 0 ⇒ x = 8

solutions are x = - 20, x = 8

However x > 0 ⇒ x = 8 and

x + 3 = 8 + 3 = 11

x + 9 = 8 + 9 = 17

Dimensions are 2cm, 11 cm, 17 cm

6 0

3 years ago

Read 2 more answers

Maria solve the equation 34 equals X +19 although her final answer was correct she could’ve found it in a simpler way what is be

tankabanditka [31]

It would be
$34 = x \ + 19$
it would be 15 because you subtract 19 from both sides and the 19's cancel so your answer would be
$x = 15$

8 0

3 years ago

Which of the following trigonometric ratios has a value that is undefined?

masya89 [10]

Answer:

it is sin C

Step-by-step explanation:

3 0

4 years ago

A track star in Arizona ran the 100 meter dash event is six track meets. Her average time for all six meets was 11.8 seconds. Sh

natima [27]

Answer:

A track star in Arizona running time in the last meet was 11.5 seconds.

Step-by-step explanation:

Given:

average time for all six meets = 11.8 seconds.

Time for 1st meet = 11.7 seconds.

Time for 2nd meet = 11.6 seconds.

Time for 3rd meet = 12 seconds.

Time for 4th meet = 12.1 seconds.

Time for 5th meet = 11.9 seconds.

We need to find the running time for her last meet.

Solution:

Let the running time for her last meet be 'x'.

So we can say that;

average time for all six meets is equal to sum of Time for 1st meet, Time for 2nd meet, Time for 3rd meet,Time for 4th meet, Time for 5th meet and time for her last meet and then divided by 6.

framing in equation form we get;

$\frac{11.7+11.6+12+12.1+11.9+x}{6}=11.8\\\\\frac{59.3+x}6 =11.8$

Now Multiplying both side by 6 we get;

$\frac{59.3+x}{6}\times 6= 11.8\times6\\\\59.3+x=70.8$

Now Subtracting both side by 59.3 we get;

$59.3+x-59.3=70.8-59.3\\\\x=11.5 \ s$

Hence A track star in Arizona running time in the last meet was 11.5 seconds.

7 0

3 years ago

a guy wire 15 ft long runs from the top of a pole to spot on the ground. if the height of the pole is 3 ft more than the distanc

Murrr4er [49]

18. The answer is 18 because the wire is 15ft and the pole is 3ft taller than the wire

6 0

3 years ago