-3
Because -2^2-8+1
-2to the second power is 4
4-8=-4
-4+1=-3
Answer:
See explanation
Step-by-step explanation:
Consider triangles ACM and BCM. In these triangles,
- given;
- definition of perpendicular lines CM and AB;
- reflexive property.
So,
by ASA postulate (if one side and two angles adjacent to this side of one triangle are congruent to one side and two angles adjacent to this side of another triangle, then two triangles are congruent).
Two-column proof:
Statement Reason
1.
Given
2.
Given
3.
Definition of perpendicular lines CM and AB
4.
Reflexive property
5.
ASA postulate

- Given - <u>A </u><u>trapezium</u><u> </u><u>ABCD </u><u>with </u><u>non </u><u>parallel </u><u>sides </u><u>of </u><u>measure </u><u>1</u><u>5</u><u> </u><u>cm </u><u>each </u><u>!</u><u> </u><u>along </u><u>,</u><u> </u><u>the </u><u>parallel </u><u>sides </u><u>are </u><u>of </u><u>measure </u><u>1</u><u>3</u><u> </u><u>cm </u><u>and </u><u>2</u><u>5</u><u> </u><u>cm</u>
- To find - <u>Area </u><u>of </u><u>trapezium</u>
Refer the figure attached ~
In the given figure ,
AB = 25 cm
BC = AD = 15 cm
CD = 13 cm
<u>Construction</u><u> </u><u>-</u>

Now , we can clearly see that AECD is a parallelogram !
AE = CD = 13 cm
Now ,

Now , In ∆ BCE ,

Now , by Heron's formula

Also ,

<u>Since </u><u>we've </u><u>obtained </u><u>the </u><u>height </u><u>now </u><u>,</u><u> </u><u>we </u><u>can </u><u>easily </u><u>find </u><u>out </u><u>the </u><u>area </u><u>of </u><u>trapezium </u><u>!</u>

hope helpful :D
Answer:-
x=-5/2
Step-by-step explanation:
x+2/3=-1/6
after cross-mutiplying,
6(x+2)=-3
6x+12=-3
6x=-3-12
6x=-15
x=-15/6
x=-5/2
hope this helps u!!