1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
TiliK225 [7]
3 years ago
12

Abby buys 1 sheet of stickers. 5 strips of ten and 9 singles. How many stickers did she buy?

Mathematics
1 answer:
Gala2k [10]3 years ago
3 0
59 stickers on one sheet
You might be interested in
Solve the system of equations 10×+7y=99andy-×=2?
djverab [1.8K]
You can use substitution and solve y-x=2 for y which is y= x+ 2 and plug it into the y of the other equasion and you get x=5 y=7
8 0
3 years ago
Find the product: 4 2/5 x 5 1/2 =
seropon [69]

Answer:

4 2/5 x 5 1/2 = 24.2

Step-by-step explanation:

PLZZ MARK BRAINLIEST!!!

6 0
3 years ago
Joshua invests​ $500 at the interest rate shown. Felix invests​ $1,000 in an account with the same compounding but at​ 6% intere
nexus9112 [7]
I need help with this too!!!!!!!!!!!!!
5 0
3 years ago
Read 2 more answers
Over the weekend, Mario bicycled 43 miles. On Sunday he rode 3 miles more than two-thirds of his distance on Saturday. Find the
aleksklad [387]
We can solve this by writing down all of the variables we know. We will call the distance traveled on Saturday, x. The distance traveled on Sunday will be y.

x = distance traveled saturday
y = distance traveled sunday

We are told that on sunday he rode 3 miles more than 2/3 the distance on saturday. We can write a new formula.

y = (2/3)x + 3

We also not the total distance travelled, x + y = 43, now we solve for x.

x + y = 43
x + (2/3)x + 3 = 43
5/3x = 40
x = 24 miles

y = (2/3)(24)+3
y = 19 miles

Therefore, Mario biked 24 miles on Saturday and 19 miles on Sunday which gives us the total of 43 miles for the whole weekend.
8 0
4 years ago
The data represent the age of world leaders on their day of inauguration. Find the​ five-number summary, and construct a boxplot
Mumz [18]

Answer:

Minimum value = 43, Q_1=52, Q_2=Median=61, Q_3=67, Maximum value = 69.

Distribution is negative skewed.

Step-by-step explanation:

The given data set is

44, 43, 67, 68, 57, 65, 52, 62, 69, 54, 53, 61, 67, 48, 65​

Arrange the data in ascending order

43, 44, 48, 52, 53, 54, 57, 61, 62, 65, 65, 67, 67, 68, 69

Divide the data in 4 equal parts.

(43, 44, 48), 52, (53, 54, 57), 61, (62, 65, 65), 67, (67, 68, 69)

Minimum value = 43

Q_1=52

Q_2=Median=61

Q_3=67

Maximum value = 69

Starting and end point of box plot represent the minimum and maximum value respectively. Box starts from the first quartile to the third quartile. A vertical line goes through the box at the median.

The shape of the distribution.

Normally distributed: If Q_3-Q_2=Q_2-Q_1

Positive skew: If Q_3-Q_2>Q_2-Q_1

Negative skew: If Q_3-Q_2

For the given data set

Q_3-Q_2=67-61=6

Q_2-Q_1=61-52=9

Since Q_3-Q_2, therefore the given distribution is negative skewed.

5 0
4 years ago
Other questions:
  • Im giving away free points, your welcome
    11·2 answers
  • Jared and Pedro walk 1 mile in about 15 minutes. They can keep this pace for several hours, how far can they walk in 90 minutes
    10·1 answer
  • Members of the Lake Shawnee Club pay $40 per summer season plus $7.50 each time they rent a boat. Non members pay $12.50 each ti
    13·1 answer
  • How many 6s are there in 285
    11·1 answer
  • Prove that x-1 is a factor of x^n-1 for any positive integer n.
    12·1 answer
  • The average of paula's two test scores must be 80 or more for her to get at least a b in the class. she got a 72 on here first t
    13·1 answer
  • I WILL MAKE YOU THE BRANLIEST
    7·1 answer
  • Taylor and Jesse are buying a magazine for $3.75 and a snack for $2.49 what is s the total cost of the two items?
    11·2 answers
  • 18+(-22.45) what does this equal?
    8·2 answers
  • Can someone help me please and thank you!!
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!