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2 years ago

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Triangle FGH is formed by connecting the midpoints of the side of triangle CDE The lengths of the sides of triangle FGH are show

n. Find the perimeter of triangle CDE. Figures not necessarily drawn to scale.

1 answer:

Vlad1618 [11]2 years ago

5 0

Answer: 36

Step-by-step explanation:

By the triangle midsegment theorem, CE=16, CD=10, and ED=10.

So, the perimeter of triangle CDE is 10+10+16=<u>36</u>

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3. Increase £60 by 10%

Serggg [28]

£66 because 60/10=6 60+6= £66

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3 years ago

Click on the photo to see it.

Lera25 [3.4K]

B is the midpoint

$\\ \sf\longmapsto AB=\dfrac{1}{2}AC$

$\\ \sf\longmapsto 7x-3=\dfrac{5}{2}$

$\\ \sf\longmapsto 5=2(7x-3)$

$\\ \sf\longmapsto 5=14x-6$

$\\ \sf\longmapsto 14x=6+5$

$\\ \sf\longmapsto 14x=11$

$\\ \sf\longmapsto x=\dfrac{11}{14}$

$\\ \sf\longmapsto x=7.8$

6 0

2 years ago

Read 2 more answers

A monitor measures 10.6 inches by 16.8 what is the length of the diagonal

Ludmilka [50]

Step-by-step explanation:

We will use pythagoras' Theorem for this question

${c}^{2} = {a}^{2} + {b}^{2}$

where c is the longest side (in this case, the diagonal)

a and b are the 2nd and 3rd longest side (interchangeable)

given a = 10.6, b = 16.8,

${c}^{2} = {10.6}^{2} + {16.8}^{2} \\ {c}^{2} = 112.36 + 282.24 \\ {c}^{2} = 394.6 \\ c = \sqrt{394.6} \\ = \frac{ \sqrt{9865} }{5} inches$

4 0

3 years ago

The coordinates of the verticies of triangle ABC are A(2,5), B(6,-1), and C(-4,-2). Fint the perimeter of triangle ABC, to the n

deff fn [24]

Answer:

24.4 Units

Step-by-step explanation:

For this, we will use the distance formula to find the distance between each vertex

$\sqrt({x_{1}-x_{2} })^{2} +(y_{1} -y_{2})^{2}$

So we do this for each side of the triangle to get AB = $\sqrt{52}$ , BC = $\sqrt{109}$ , and AC = $\sqrt{45}$

We add these all up to get 24.4 (rounded)

8 0

2 years ago

Help me, please !!!!

ehidna [41]

20 and 3/4 is 20.75
20 and 7/8 is 20.875
20 and 1/5 is 20.2
20 and 4/5 is 20.8

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2 years ago