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2 years ago

15

Suppose you invest $1700 at an annual interest rate of 8.8% compounded continuously. How much will you have in the account after

7.5 years?

2 answers:

Fittoniya [83]2 years ago

8 0

Answer:

after 7.5 years you will have: 3200.11

The total compound interest is 1,447.56.

Step-by-step explanation:

$\frac{8.8}{100} = 0.088\\1700(1+0.088)^{7.5} = 3200.11\\$

shepuryov [24]2 years ago

4 0

After 7.5 years, you will have $3,200.12

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How do i <br> Evaluate 4!.

Wewaii [24]

Hello there!

The formula is
N! = n(n -1)(n - 2)
Now all we have to do is replace N by 4
N! = 4(4-1)(4-2)
= (4)(3)(4-2)
= (12)(2)
= 24
Here you go, the answer is : 24

I hope this answer help! Good luck with your studies.

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3 years ago

Figure ABCD is a rectangle Find the value of x

romanna [79]

Step-by-step explanation:

Since this is a rectangle these two equations for the length have to equal each other.

2x+4=7x-1

We now need to get all of the x's on one side and constant numbers on the other side.

add 1 to both sides and subtract 2x from both sides.

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3 years ago

What is the answer to 3 x minus equals 5

agasfer [191]

3x - 5 =

divide 3 on both sides

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3 years ago

The mass of one methane molecule is 2.7x10^-23gram. Find the mass of 90,000 molecules of methane. Express the answer in scientif

melomori [17]

Answer:

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3 years ago

A distributor of personal computers has five locations in a city. In the year's first quarter, the sales in units were: Location

Deffense [45]

Answer:

The correct option is (c) 13.277.

Step-by-step explanation:

The observed data is:

Location Observed sales (units)

Northside 70

Pleasant Township 75

Southwick 70

I-90 50

Venice Avenue 35

TOTAL 300

The test statistic for the Goodness of fit test is:

$\chi^{2}=\sum\frac{(Observed-Expected)^{2}}{Expected}$

For <em>k</em> independent samples this test statistic follows a Chi-square distribution with degrees of freedom (<em>k</em> - 1).

The sample size in this case is, <em>k</em> = 5.

The degrees of freedom is, (<em>k</em> - 1) = 4.

The level of significance is, <em>α</em> = 0.01.

The critical value of the test is:

$\chi^{2}_{\alpha ,k-1}=\chi^{2}_{0.01,4}=13.277$

**Use the Chi-square table.

Thus, the critical value is 13.277.

7 0

3 years ago