Question

Suppose a basketball player is an excellent free throw shooter and makes 94​% of his free throws​ (i.e., he has a 94​% chance of making a single free​ throw). assume that free throw shots are independent of one another. suppose this player gets to shoot three free throws. find the probability that he misses all three consecutive free throws. round to the nearest​ ten-thousandth.

Answer 1

Probability of a failure on 1 throw = 1 - 0.94 = 0.06 or 6%.

Prob (he misses all 3) = 0.06^3 = 0.000216 = 0.0002 to nearest ten thousandth