It’s a little complicated but here’s how it works:
Imagine a table with the intervals
0:4 , 4:6 , 6:7 , 7:10 , 10:13 (10 year intervals)
Then we have different rows
Class width: 4 , 2 , 1 , 3 , 3
Freq density: 0.2 , 0.5 , 1.2 , 0.7 , 0.3
So now calculate frequency where freq = class width * density
Freq: 0.8 , 1 , 3.6 , 2.1 , 0.9
So to find median find cumulative frequency
(Add all freq)
Cfreq = 8.4 now divide by 2 = 4.2
So find the interval where 4.2 lies.
0.8 + 1 = 1.8 + 3.6 = 5.6
So 4.2 (median) will lie in that interval 60-70 years.
C. 0.04 would be the correct answer.
Answer:
less than
Step-by-step explanation:
x = 0(number of pictures) 3 * 0 = 0
0 is less than 8 :)
Answer:
y = (1/4)x
Step-by-step explanation:
"Direct variation" here signifies y = kx, where k is the constant of proportionality.
Then y = kx. Here we are to find k using the info that x = 12 and y = 3:
3 = k(12), or
k = 3/12, or k = 1/4
Then y = (1/4)x
The answer is 2. Here's why:
First if all, anything to the power of 0 is 1.
So n^0=1.
You need to plug in 3 for m, so then 6(3)^-1.
3^-1=1/3.
6 × 1/3= 6/3=2
2×1=2.
