2 years ago

-2m(m + n - 4) + 5(-2m + 2n) + n(m + 4n - 5)

Mathematics

1 answer:

e-lub [12.9K]2 years ago

6 0

I provided the answer in photo

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What is the 32nd term of the arithmetic sequence where a1 = 12 and a13 = -60

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Answer:

The 32nd term of Arithmetic sequence is -174

Step-by-step explanation:

Given: $a_1=12, a_{13}=-60$

We are given two term of the Arithmetic sequence.

Formula:

$a_n=a+(n-1)d$

For $a_1=12$

$a=12$

For $a_{13}=-60$

$a+12d=-60$

Using two equation solve for a and d

$12+12d=-60$

$1+d=-5$

$d=-6$

We need to find 32nd term

$a_{32}=a+31d$

$a_{32}=12+31(-6)$

$a_{32}=12-186$

$a_{32}=-174$

Hence, The 32nd term of Arithmetic sequence is -174

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Step-by-step explanation:

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What is 2x + 18 = 20?????

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Hello there!

Just solve for x by combining like terms:

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