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sveticcg [70]
4 years ago
9

Solise is planting 24 bushes and 16 trees in equal rows. She wants all the rows to be exactly the same with no plants left over.

What is the greatest number of rows Solise can plant?
Mathematics
1 answer:
ZanzabumX [31]4 years ago
5 0

━━━━━━━━━━━━━━━ ♡ ━━━━━━━━━━━━━━━  

Since Solise want to plant both trees and bushes in the same number of rows, you need to find the common factor.

Since the question is asking what the greatest number of rows she can plant, you have to find the greatest common factor.

The greatest common factor of 24 and 16 is 8.

You can plant 24 bushes in 8 rows (meaning you can divide it by 8), and 16 trees in 8 rows (meaning you can divide it by 8). Since the greatest number you can divide them both by is 8, the GCF of 24 and 16 is 8.

So the greatest number of rows Solise can plant is 8 rows.

━━━━━━━━━━━━━━━ ♡ ━━━━━━━━━━━━━━━  

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find the values of x and y that make these triangles congruent by the hl theorem x=2,y=3 x=-2,y=3x=3,y=2x=4,y=8
AnnyKZ [126]

Answer:

The correct option is x=3 , y=2

Step-by-step explanation:

According to the HL theorem if the hypotenuse and one leg of a right triangle are congruent to the hypotenuse and one leg of another right triangle then the triangles are congruent.

By using this theorem we can set up the system of equations as follows:

x=y+1 ...(1)

2x+3= 3y + 3 ..(2)

Now we will plug the value y+1 of equation 1 in equation 2.

2x+3 = 3y+3

2(y+1)+3=3y+3

2y+2+3=3y+3

2y+5=3y+3

Now combine the like terms:

5-3=3y-2y

2=y

y=2

Now plug the value y=2 in equation 1.

x=y+1

x=2+1

x=3

Thus the values of(x.y) are{(2,3)}

Therefore the correct option is x=3 , y=2 .....

3 0
3 years ago
It is believed that Lake Tahoe Community College (LTCC) Intermediate Algebra students get less than seven hours of sleep per nig
Kitty [74]

Answer: No , at 0.05 level of significance , we have sufficient evidence to reject the claim that LTCC Intermediate Algebra students get less than seven hours of sleep per night, on average.

Step-by-step explanation:

Let \mu denotes the average hours of sleep per night.

As per given , we have

H_0:\mu=7\\H_a:\mu

, since H_a is left-tailed and population standard deviation is unknown, so the test is a left-tailed t -test.

Also , it is given that ,

Sample size : n= 22

Sample mean : \overline{x}=7.24

Sample  standard deviation : s= 1.93

Test statistic : t=\dfrac{\overline{x}-\mu}{\dfrac{s}{\sqrt{n}}}

i.e.  t=\dfrac{7.24-7}{\dfrac{1.93}{\sqrt{22}}}\approx0.58

For significance level \alpha=0.05 and degree of freedom 21 (df=n-1),

Critical t-value for left-tailed test= t_{\alpha, df}=t_{0.05,21}=- 1.7207

Decision : Since the test statistic value (0.58) > critical value  1.7207, it means we are failed to reject the null hypothesis .

[Note : When |t_{cal}|>|t_{cri}|, then we accept the null hypothesis.]

Conclusion: We have sufficient evidence to reject the claim that LTCC Intermediate Algebra students get less than seven hours of sleep per night, on average.

6 0
3 years ago
Solve 23456789123456789÷2​
aniked [119]
Answer;
It’s 1.1728395e+16
8 0
3 years ago
Read 2 more answers
Yuson must complete 210 min of community service. She does 30 min each day. Which linear equation represents the number of minut
Misha Larkins [42]

Answer:

y=-30x+210

Step-by-step explanation:

Let

x -----> the number of days

y ----> the number of minutes Yuson has left

we know that

The linear equation in slope intercept form is equal to

y=mx+b

where

m is the slope

b is the y-coordinate of the y-intercept (initial value)

In this problem we have

The slope is equal to

m=-30\frac{min}{day} ----> is negative because is a decreasing function

b=210\ min ----> initial value

substitute the values

y=-30x+210

3 0
4 years ago
PLEASE HELP! WILL MAKE YOU THE BRAINLIEST IF YOU ARE THE FIRST PERSON
kow [346]

According to formula

Time in hours = d/2 + e/2

where d=distance in miles

e=difference in elevation in 1000 ft.

Therefore

d=9 miles

e=9000 ft/1000 ft = 9

Time in hours

= d/2 + e/2

= 9/2 +  9/2

= 9 hours.

8 0
4 years ago
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