Answer:
Since this is a linear (non-exponential) population problem you can just use the standard y=mx+b form of an equation. Where m = (change in population/change in years)
The numbers you were provided state that over the course of 7 years (1998-1991) the population increased by 420 people (4130-3710). So, (420/7) = 60 = m. Assuming that the growth rate for 1990 is the same as 1991. then you would have a starting population of (3710-60) or 3650, that would be your "b" value since at t=0 P(t) = 3650. This yields a final equation of P(t) = 60t +3650. Check the answer at t=1 and you get the population during 1991: 3710.
Step-by-step explanation:
.
Plug it into the distance formula.
d= (sqrt) (x2-x1)^2 +(y2-y1)^2
d= (sqrt) (17-17)^2 + (33-(-21)^2
d=(sqrt) (0)^2 + (33 +21)^2
d= (sqrt) (54)^2
d= (sqrt) 2916
d=54
The distance is 54 units.
I hope this helps!
~kaikers
Answer:
<LKJ = 115°
Step-by-step explanation:
<LKJ = <LKD + <DKJ
<LKJ = 60°+55°
<LKJ = 115°
Answered by GAUTHMATH
<span>Multiply the number in the tens place of the bottom number by the number in hundreds place of the top number. Multiply 3 times 7 to equal 21. Add the 1 you carried to equal 22. You don't need to carry the 2 in 22, as there are no more numbers to multiply on this line, so you can just write it down next to the 6.</span>
