We know the opposite side (10) and the adjacent side (7), so we can use tangent to find angle B. Since tan = opposite side/adjacent side, we can set up this equation: tan(B) = 10/7. We can get B on its own by making the equation this:
Now, we plug this into our calculator to get:
B = 55°, so angle B is 55°.
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Say the percentage increase is 25%. If you have the whole number of 30 then you would multiply 30 by .25. You should therefore get 7.5 once both are multiplied. That means you should add 7.5 to 30, and your final answer will be 37.5.
Answer:
D.
Step-by-step explanation:
Since we're using exponential decay, the answer would have to be less than 1.00, already eliminating A, B, and C. 1.00 - .12 = .88, which proves that D is our answer. Hope this helped! If you could, please mark brainliest if it's right.
Answer:
765 J
Step-by-step explanation:
We are given;
Mass of bucket = 30 kg
Mass of rope = 0.3 kg/m
height of building= 30 meter
Now,
work done lifting the bucket (sand and rope) to the building = work done in lifting the rope + work done in lifting the sand
Or W = W1 + W2
Work done in lifting the rope is given as,
W1 = Force x displacement
W1 = (30,0)∫(0.2x .dx)
Integrating, we have;
W1 = [0.2x²/2] at boundary of 30 and 0
W1 = 0.1(30²)
W1 = 90 J
work done in lifting the sand is given as;
W2 = (30,0)∫(F .dx)
F = mx + c
Where, c = 30 - 15 = 15
m = (30 - 15)/(30 - 0)
m = 15/30 = 0.5
So,
F = 0.5x + 15
Thus,
W2 = (30,0)∫(0.5x + 15 .dx)
Integrating, we have;
W2 = (0.5x²/2) + 15x at boundary of 30 and 0
So,
W2 = (0.5 × 30²)/2) + 15(30)
W2 = 225 + 450
W2 = 675 J
Therefore,
work done lifting the bucket (sand and rope) to the top of the building,
W = 90 + 675
W = 765 J
