Question

Suppose that c varies jointly with d and the square of g, and c = 30 when d = 15 and g = 2.

Answer 1

Answer:

$d = \dfrac{3}{16}$

Step-by-step explanation:

c varies jointly with d and the square of g

$c\propto dg^2$

$c=kdg^2$

where, k is constant of proportionality.

Put the given value c = 30 when d = 15 and g = 2 and find out k

$30=k\cdot 15\cdot 2^2$

$k=\dfrac{1}{2}$

$c=\dfrac{1}{2}kg^2$

If c = 6 and g = 8 then d = ?

$6=\dfrac{1}{2}\cdot d\cdot 8^2$

$d=\dfrac{6\cdot 2}{8^2}$

$d=\dfrac{3}{16}$

Hence, The value of d is $\dfrac{3}{16}$