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2 years ago

8

Calculate the distance between (2, -2) and (-3, -1).

1 answer:

Elena L [17]2 years ago

6 0

Answer:5.1

Step-by-step explanation:

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If the Discriminant of an equation is zero, which of the following is true of the equation?

VARVARA [1.3K]

Answer:

a) it has one real solution

5 0

3 years ago

A baby bird jumps from a tree branch and flutters to the ground. The function "f" models the bird's height (in meters) above the

AURORKA [14]

The answer to this question will depend on the function f itself. Basically you will find the height in meters above the ground of the bird when it jumped when the time t=0s. This is substsitute every t in the function for a value of zero and that way you will get the bird's height at the time it jumped. If you were given a graph for this function, you can find the y-intercept of the graph and that will be the answer as well. The question could be written like this:

A baby bird jumps from a tree branch and flutters to the ground. The function " $f(t)-4.9t^{2}+25$ " models the bird's height (in meters) above the ground as a function of time (in seconds) after jumping. What is bird's height above the ground when it jumped.

Answer:

25m

Step-by-step explanation:

Once your function is given, you can substitute t=0 since 0s is the time measured at the moment the bird jumped. So our function will be:

$f(0)=-4.9(0)^2+25$

$f(0)=25m$

So the height of the bird above the ground when it jumped is 25m in this particular function.

8 0

2 years ago

If a/b < c/d with b > 0, d > 0, prove that a+c / b+d lies between the two fractions a/b and c/d .

Tems11 [23]

Divide through everything by <em>b</em> :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ab + \dfrac cb}{1 + \dfrac db}$

Since <em>a/b</em> < <em>c/d</em>, it follows that

$\dfrac{a+c}{b+d} < \dfrac{\dfrac cd+\dfrac cb}{1 + \dfrac db}$

Multiply through everything on the right side by <em>b/d</em> to get

$\dfrac{a+c}{b+d} < \dfrac{\dfrac{bc}{d^2}+\dfrac cd}{\dfrac bd+1} = \dfrac{\dfrac cd\left(\dfrac bd+1\right)}{\dfrac bd+1} = \dfrac cd$

and so (<em>a</em> + <em>c</em>)/(<em>b</em> + <em>d</em>) < <em>c/d</em>.

For the other side, you can do something similar and divide through everything by <em>d</em> :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ad + \dfrac cd}{\dfrac bd + 1}$

and <em>a/b</em> < <em>c/d</em> tells us that

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ad + \dfrac ab}{\dfrac bd + 1}$

Then

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ab + \dfrac{ad}{b^2}}{1 + \dfrac db} = \dfrac{\dfrac ab\left(1+\dfrac db\right)}{1 + \dfrac db} = \dfrac ab$

and so (<em>a</em> + <em>c</em>)/(<em>b</em> + <em>d</em>) > <em>a/b</em>.

Then together we get the desired inequality.

5 0

3 years ago

The Student Athletes Club has a

devlian [24]

Answer:

Step-by-step explanation:

3 0

2 years ago

1) What is the volume of this aquarium?<br> 5 in.<br> 6 in.<br> 5 in.<br> 10 in.<br> 18 in.

Flura [38]

Which one is the length, height, and width? After you that then multiple and you should have your answer. Hope this helps!

4 0

2 years ago