Answer:
35 because i had this problem before and the answer was 35 cuz yeah
The cost of children’s ticket is $ 5
<h3><u>Solution:</u></h3>
Let "c" be the cost of one children ticket
Let "a" be the cost of one adult ticket
Given that adult ticket to a museum costs 3$ more than a children’s ticket
<em>Cost of one adult ticket = 3 + cost of one children ticket</em>
a = 3 + c ------ eqn 1
<em><u>Given that 200 adult tickets and 100 children tickets are sold, the total revenue is $2100</u></em>
200 adult tickets x cost of one adult ticket + 100 children tickets x cost of one children ticket = 2100

200a + 100c = 2100 ------ eqn 2
<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "c"</u></em>
Substitute eqn 1 in eqn 2
200(3 + c) + 100c = 2100
600 + 200c + 100c = 2100
600 + 300c = 2100
300c = 1500
<h3>c = 5</h3>
Thus the cost of children’s ticket is $ 5
Circumference=2 x pi x radius
radius= diameter/2= 28/2= 14 ft.
c=2 x 3.14 x 14
c= 87.92 ft. or rounded to 88 feet
The population of the group in 2019 is 2,134,000 people
Let P represent the population in thousands of people in the year t after 2011
Given the equation:

a) The population of the group in 2019, that is t = 8(2019 - 2011):

b) The population of the group in 2029, that is t = 18(2029 - 2011):

The population of the group in 2019 is 2,134,000 people
Find out more on equation at: brainly.com/question/2972832
3(5)-15+10(7)-2(5)
15-15+70-10
=60
The answer is 60