Step-by-step explanation:
Here, f(x) is the given polynomial.
By remainder Theorem,
When divided by (3x-1),
f(1/3) = -3........(1)
When divided by (x+1),
f(-1) = -7.........(2)
<em>Another</em><em> </em><em>polynomial</em><em> </em><em>is</em><em> </em><em>3</em><em>x</em><em>²</em><em>+</em><em>2</em><em>x</em><em>-</em><em>1</em>
Solving,
3x²+2x-1
= 3x²+3x-x-1
=3x(x+1)-(x+1)
=(3x-1)(x+1)
So
f(x) = (3x-1)(x+1)Qx + (ax+b)
For f(-1),
-7 = -a+b
b= a-7
For f(1/3),
-3 = a/3+b
or, -3 = a/3+a-7
or, 4×3 = 4a
or a = 3
Also, b = 3-7 =-4
Hence, remainder is (3x-4)
Answer:
x^4/21
Step-by-step explanation:
Answer:
The anwser is always Jesus
Step-by-step explanation:
Also there is no following
Answer:
1÷8and 5 than 6.16,6.107.
,121÷20.hope that help
