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Stells [14]
3 years ago
12

A

Mathematics
1 answer:
DIA [1.3K]3 years ago
5 0

Answer:

qwertyuo;kjghjkl;'

Step-by-step explanation:

43r567890op0oy76t43rtbhjm,ju765

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fgiga [73]

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Answer:

Below in bold.

Step-by-step explanation:

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The line defined by the equation 2y+3=-(2/3)(x-3) is tangent to the graph of g(x) at x=-3. What is the value of the limit as x a
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<span>the limit as x approaches -3 of [g(x)-g(-3)]over(x+3) is the same as the derivative, or slope, of g(x) at the point x=-3, or g'(-3).
Since you are given the equation of the tangent line, the answer is just the slope of that line.
</span><span>2y+3=-(2/3)(x-3)
</span><span>6y+9=-2(x-3)
6y+9=-2x+6
6y=-2x-3
y= (-2x-3)/6
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3 years ago
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Step-by-step explanation:

just putting in words give me points so

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Volgvan

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Step-by-step explanation:

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