Option C
The ratio for the volumes of two similar cylinders is 8 : 27
<h3><u>
Solution:</u></h3>
Let there are two cylinder of heights "h" and "H"
Also radius to be "r" and "R"

Where π = 3.14 , r is the radius and h is the height
Now the ratio of their heights and radii is 2:3 .i.e

<em><u>Ratio for the volumes of two cylinders</u></em>

Cancelling the common terms, we get

Substituting we get,



Hence, the ratio of volume of two cylinders is 8 : 27
Answer:
(-1,1,3)
Step-by-step explanation:
midpoint = (x1+x2/2, y1+y2/2, z1+z2/2)
midpoint = ( (-6+4)/2, (3+-1)/2, (4+2)/2 )
midpoint = (-2/2, 2/2, 6/2)
midpoint = (-1, 1, 3)
Answer:
y=25*2ˣ.
Step-by-step explanation:
no details.
3x² - 33x - 180 = 0
3(x² - 11x - 60) = 0
3(x² - 15x + 4x - 60) = 0
3(x + 4)(x - 15) = 0
3(x - 4) = 0 or x - 15 = 0
3x - 12 = 0 <u> + 15 + 15</u>
<u> + 12 + 12</u> x = 15
<u>3x</u> = <u>12</u>
3 4
x = 3
The answer is equal to H.15 and E. 4.
X = approximately 633
Steps:
lnx + ln3x = 14
ln3x^2 = 14 : Use the log property of addition which is to multiply same log together so you multiply x and 3x because they have log in common
(ln3x^2) = (14) : take base of e on both sides to get rid of the log
e e
3x^2 = e^14 : e cancels out log on the left side and the right side is e^14
x^2 = e^14 / 3 : divide both sides by 3
√x^2 = <span>√(e^14 / 3) : take square root on both sides to get rid of the square 2 on x
</span>
x = √(e^14) / <span>√3 : square root cancels out square 2 leaving x by itself
x = e^7 / </span>√3 : simplify the √(e^14) so 14 (e^14) divide by 2 (square root) = 7<span>
x = </span>633.141449221 : solve