Answer:
<h2>C</h2>
Explanation:
Each protein has <em><u>its own unique sequence of</u></em> <em><u>amino acids</u></em> and the interactions between these amino acids create a specify shape. This shape determines the protein's function, from digesting protein in the stomach to carrying oxygen in the blood.
Answer:
D. Fatty Acids
Explanation:
When fatty acids undergo beta-oxidation to serve as a source of ATPs, ketone bodies are produced. During starvation or medical conditions such as diabetes mellitus, carbohydrate supply to liver cells is depleted.
Once the stored glycogen has been depleted from the liver cells, the fatty acids are funneled into beta-oxidation to produce ATPs. The process also forms acetone, acetoacetate, and D-beta-hydroxybutyrate, that is the ketone bodies. The more the fatty acid molecules enter the beta oxidation, the more ketone bodies are produced.
The question is incomplete, however, the statements associated with this question is given in the comments and here as well:
Neither facilitated diffusion nor osmosis requires cell energy.
Diffusion of gases and other small molecules requires no energy on the part of the cell.
Active transport requires cell energy and osmosis doesn't.
Both endocytosis and active transport require cell energy.
Answer:
The correct answer is - Active transport requires cell energy and osmosis doesn't.
Explanation:
Osmosis is an example of passive transport as it does not require energy to facilitate the movement of solvent In the process of osmosis,. It moves from high concentration to low concentration through the semipermeable membrane which is along the gradient so no requirement of energy.
In the case of Active transport, it requires energy to facilitate the movement of transport as it is the movement of a substance from low concentration to a high concentration area that is against the concentration gradient.
Answer 1,2,3,4:
As both are heterozygous therefore Male genotype will be (BbEe) and the genotype of female will be (BbEe). While both will have the phenotype black.
Parent Genotype
Male X Female
BbEe X BbEe
Possible gametes from Parents
Male X Female
BbEe X BbEe
(BE) (Be) (bE) (be) X (BE) (Be) (bE) (be)
...
F1 generation will have following genetypic ratio
Black Labrador = 9 = B_E_
Brown Labrador = 3 = bbE_
Yellow Labrador = 3 = B_ee
Yellow Labrador = 1 = bbee
Furthermore, the phenotypic ration will be
Black Labrador = 9
Brown Labrador = 3
Yellow Labrador = 4
