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Contact [7]
3 years ago
9

Pls open first to answer correctly get brainlist

Mathematics
2 answers:
KengaRu [80]3 years ago
5 0

Answer:

C AND D

Step-by-step explanation:

it is a rational and real number

omeli [17]3 years ago
3 0

Answer:

\Large \boxed{\mathrm{\bold{C.} \ real}} \\\\ \Large \boxed{\mathrm{\bold{D.} \ rational}}

Step-by-step explanation:

\sf \displaystyle \frac{5}{6}=0.833333...

The fraction is a repeating decimal. Repeating decimals are rational numbers.

A rational number is a real number.

You might be interested in
Find D
Snowcat [4.5K]

Answer:

b. < D = 64°

I hope this helps

7 0
3 years ago
Read 2 more answers
Select the correct answer from each drop-down menu.
9966 [12]

Answer:

(0.392 ; 0.508)

Step-by-step explanation:

Given that :

p = 45% = 0.45

α = 1 - 90% = 0.1

Zα/2 = Z0.01/2 = Z0.05 = 1.645 (from Z standard table).

Using the relation :

p ± Z0.05*sqrt((p(1-p))/n)

p ± 1.645 * sqrt(0.45(0.55)/200)

p ± 1.645 * sqrt(0.0012375)

p ± 1.645 *0.0351781

0.45 - (1.645 * 0.0351781) = 0.3921320255

0.45 + (1.645 * 0.0351781) = 0.5078679745

(0.392 ; 0.508)

4 0
3 years ago
Read 2 more answers
I need help i dont know the answers
Arlecino [84]

Answer: Change the number: 36

To:48

Step-by-step explanation:

12x2 is 24 but 24 x 2 isn’t 36

5 0
3 years ago
1 2 (–1.4m + 0.4) = m + 0.2
allsm [11]

First, you need to get rid of the parenthesis, so you need to distribute:

12(–1.4m + 0.4) = m + 0.2

-16.8m + 4.8 = m +0.2

Then subtract both sides by m:

-16.8m - m + 4.8 = m +0.2 - m

-17.8m + 4.8 = 0.2

Subtract both sides by 4.8:

-17.8m + 4.8 - 4.8 = 0.2 - 4.8

-17.8m = -4.6

Now, divide both sides by -17.8:

-17.8m/-17.8 = -4.6/-17.8

m ≈ 0.258

8 0
3 years ago
g On any day, the probability of rain is 0.3. The occurrence of rain on any day is independent of the occurrence of rain on any
Ksju [112]

Answer:

0.249579

Step-by-step explanation:

P(rain) = 0.3

P(no rain) = 1 - 0.3 = 0.7

The event of rain falling a second time within the next 5 days is possible in these ways

1. Rain on days 1 and 2

2. Rain on days 1 and 3; none on day 2

3. Rain on days 1 and 4; none on days 2 and 3

4. Rain on days 1 and 5; none on days 2, 3 and 4

5. Rain on days 1 and 6; none on day 2, 3, 4 and 5

P(\text{second rain within 5 days}) = 0.3^2+0.3^2\times0.7+0.3^2\times0.7^2+0.3^2\times0.7^3+0.3^2\times0.7^4 = 0.3^2(1+0.7+0.7^2+0.7^3+0.7^4)= 0.09\times2.7731=0.249579

5 0
4 years ago
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