Answer:
Distance covered by hula hoop rolls in 4 full rotations is 880 cm .
Step-by-step explanation:
Formula
Where r is the radius of the circle.
As given
Allison is rolling her hula hoop on the playground.
The radius of her hula hoop is 35 cm.
r = 35 cm
Putting the value in the formula
= 220 cm
As given
The hula hoop rolls in 4 full rotations.
Distance covered by hula hoop rolls in 4 full rotations = 220 × 4
= 880 cm
Therefore the Distance covered by hula hoop rolls in 4 full rotations is 880 cm .
Answer: this question may be easier to answer if you actually graph it. You can also use the app Desmos on the AppStore which is free to find the solution.
Step-by-step explanation:
Answer:
y=2/3x+1
Step-by-step explanation:
using the slope intercept formula, y=mx+b, where m is the slope, and b is the y intercept. So we get the equation y=2/3x+b, because the slope is given, then you use the given point and substitute it into the equation, 5=2/3(6)+b which you can solve and you will get 5=4+b, b =1, then you add 1 to your original equation to get your answer, y=2/3x+1
Answer:
Let the distance between woman and pole be "x".
From diagram,
In ΔOAB,
tan 18 = 
tan 18 = 
∴ x = 
................ (1)
In ΔOBC
tan 14 =
tan 14 = 
y = x × tan 14 ..............(2)
equating (2) in (1), we get;
x = 
x = 
∵ tan 18 + tan 14 = 0.574
<em>∴ x = 113.2 ft</em>
<em>i.e. The her distance from the pole is 113.2 ft.</em>
In triangle ABC and DEF
AC =DF, [ given ]
AB =DE, [ given ]
angle A = angle D
by SAS
ABC congruent to triangle DFE
so
BC = EF, [ CPCTC]
hence proved
