All categories

3 years ago

Parallel lines e and f are cut by transversal b what is the value of x?

Mathematics

2 answers:

yuradex [85]3 years ago

5 0

Answer:

Step-by-step explanation:

Both lines are being cut by the same transversal so to solve for x, we have to make both equations equal to each other( 2x+10 = 3x-15) isolate x or 3x ( the inverse operations ). Add 15 to 10 (10+15=25) which turns into 2x+25=3x. Combine the x values (25=3x-2x) which results in 25=1x. Divide both sides to complete the problem, which would give you x=25

NikAS [45]3 years ago

4 0

Answer: 25

Step-by-step explanation:

Both lines are being cut by the same transversal so to solve for x, make both equations equal to each other

2x+10 = 3x-15

To isolate x, do the inverse operations (for any side chosen)

Do the inverse operations to move -15 and isolate 3x

Add 15 to 10 (10+15=25)

You now have 2x+25=3x

Now, do the same to combine the x values together

25=3x-2x

You now have 25=1x

Divide by 1 on both sides

25=x

You might be interested in

Mr. Bloop can high jump 5.75 feet. How far short is that of Charles Austin's record of 7 ft 10 in?

a_sh-v [17]

Answer:

5.75 feet is the same as 5 ft 9 inches (because 12 in = 1 ft and 0.75 * 12 = 9 so its 9 in). 7 ft 10 in - 5 ft 9 in = 2 ft 1 in.

6 0

3 years ago

Solve for x and y by substitution method

zubka84 [21]

Answer:

Step-by-step explanation:

Because if you simplify you get that

3 0

2 years ago

Read 2 more answers

Factor each.<br><br><br> Please help!

Naddika [18.5K]

Answer:

1) The factors of $x^2-3x+2=0$ are $\mathbf{(x-1)(x-2)=0}$

Option C is correct.

3) The factors of $x^2+2x-8=0$ are $\mathbf{(x-2)(x+4)=0}$

Option B is correct.

Step-by-step explanation:

1) Factor : $x^2-3x+2=0$

For factoring we need to break the middle term, such that there sum is equal to middle term of expression and product is equal to product of first and last term.

The middle term : -3x

We can break them as (-2x)( -x)

Solving:

$x^2-3x+2=0\\x^2-2x-x+2=0\\x(x-2)-1(x-2)=0\\(x-1)(x-2)=0$

So, factors of $x^2-3x+2=0$ are $\mathbf{(x-1)(x-2)=0}$

Option C is correct.

3) Factor: $x^2+2x-8=0$

For factoring we need to break the middle term, such that there sum is equal to middle term of expression and product is equal to product of first and last term.

The middle term : 2x

We can break them as (4x)( -2x)

Solving

$x^2+2x-8=0\\x^2+4x-2x-8=0\\x(x+4)-2(x+4)=0\\(x-2)(x+4)=0$

So, factors of $x^2+2x-8=0$ are $\mathbf{(x-2)(x+4)=0}$

Option B is correct.

7 0

2 years ago

Question

EleoNora [17]

Answer:

students in the drama club: 57

students in the yearbook club: 44

Step-by-step explanation:

101 - 13 = 88

88 / 2 = 44

101 - 44 = 57

44 in the drama club and 57 in the yearbook club

5 0

1 year ago

Translation: 6 units right and 3 units down<br> s(-3, 3), C(-1, 4), W(-2,-1)

sdas [7]

S (3, 0)
C (5, 1)
W (4, -4)

Explanation
You take the first number and add 6 to it and you get the new number and then you take the second number and subtract 3 from it

S: -3 + 6 = 3
S- 3 - 3 = 0

C: -1 + 6 = 5
C: 4 - 3 = 1

W: -2 + 6 = 4
W: -1 - 3 = -4

3 0

2 years ago