Question

Differential Equations

Answer 1

Answer:

$b=\pm2\sqrt{2}$

Step-by-step explanation:

For the spring mass system

my"+by'+ky=0

The system is said to be critically damped if $b^2-4mk=0$

Here b is coefficient of friction

m is the mass of system

And k is spring constant

We have given m = 2 kg , k =1

So $b^2-4\times 2\times 1=0$

$b^2=8$

$b=\pm2\sqrt{2}$

So the coefficient of friction is $\pm2\sqrt{2}$