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4 years ago

8

Write an expression that, when simplified is equivalent to 15x +7

1 answer:

cupoosta [38]4 years ago

4 0

Answer:

2(7.5x+3.5)

Step-by-step explanation:

I can't remember what these equations are actually called, however in order to solve this you simply multiply 7.5 by 2, and then 3.5 by 2.

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Algebra homework question pls answer.

Arada [10]

Answer:

um I think it's f I'm not sure tho

4 0

3 years ago

Read 2 more answers

The average white rhinoceros gives birth to a single calf that weighs about 3.8% as much as its mother. If the mother rhinoceros

USPshnik [31]

There are 2000 pounds in a ton - so the rino weighs 3.75 x 2000 = 7500 pounds

a percentage can be converted to a decimal - if you want to know what 3.8% of a number is, move the decimal two spaces to the left 3.8% is 0.038 -

Multiply 7500 pounds by 0.038 - the answer is 285 pounds.

4 0

3 years ago

Compute the amount of interest earned in the following simple interest problem.

Mumz [18]

Answer:

Step-by-step explanation:

P = $295

r =7%

t = 270 days = 270/365

Interest = Prt

$=295*\frac{7}{100}*\frac{270}{365}\\\\= 15.28$

= $ 15.28

Amount = 295 + 15.28

Amount = $310.28

4 0

3 years ago

Factor 2x^2 - 2x - 12

Pavlova-9 [17]

Factor the polynomial.

2(x−3) (x+2)

How to get the answer:

Factor 2x^2−2x−12

2x^2−2x−12

=2(x+2)(x−3)

Answer: 2(x+2)(x−3)

8 0

3 years ago

A manufacturer makes chocolate squares that have a target weight of 8 g. Quality control engineers sample 30 chocolate squares t

posledela

Using the <em>normal distribution and the central limit theorem</em>, it is found that the power of the test is of 0.9992 = 99.92%.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

In this problem:

The mean is $\mu = 8.5$ .

The standard deviation is $\sigma = 0.87$ .

A sample of 30 is taken, hence $n = 30, s = \frac{0.87}{\sqrt{30}} = 0.1588$ .

The power of the test is given by the probability of a sample mean above 8, which is <u>1 subtracted by the p-value of Z when X = 8</u>, so:

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem:

$Z = \frac{X - \mu}{s}$

$Z = \frac{8 - 8.5}{0.1588}$

$Z = -3.15$

$Z = -3.15$ has a p-value of 0.0008.

1 - 0.0008 = 0.9992.

The power of the test is of 0.9992 = 99.92%.

To learn more about the <em>normal distribution and the central limit theorem</em>, you can check brainly.com/question/24663213

5 0

3 years ago