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2 years ago

Y – 10 = -2(x + 9)

Mathematics

1 answer:

kolbaska11 [484]2 years ago

5 0

Answer:

slope intercept form

y=-2x-8

m=-2

y-intercept = (0,-8)

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Write the numbers three hundred and fifty-four thousand, two hundred and ten in figures (354,210).

GalinKa [24]

Answer:

Three hundred and fifty-four thousand, two hundred and ten =354210

Hundred thousand║Ten thousand║Thousand║Hundred║Tens║Ones

3 5 4 2 1 0

Step-by-step explanation:

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1 year ago

When an object with a momentum of 80 kg ´ m/s collides with an object with a momentum of –100 kg ´ m/s the total momentum after

mojhsa [17]

This is a physics problem.

The law is that the momentum is preserved: total momentum before collsion = total momentum after collision

Momentum before collision = 80 kg.m/s - 100 kg.m/s = -20 kg.m/s

Then answer is b. - 20 kg.m/s

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2 years ago

There are 50 apple trees in an orchard. Each tree produces 800 apples. For each additional tree planted in the orchard, the outp

Mariana [72]

Answer:

<em> 15</em>
<em> 42,250</em>

Step-by-step explanation:

The given function is,

$P=40000+300x-10x^2$

where,

P = the total production of apples,

x = the number of trees added.

As the quadratic function has a negative leading coefficient, so it will open downward and at the vertex the value of function is maximum.

The vertex will be at $\left(-\dfrac{b}{2a},-f\left(\dfrac{b}{2a}\right )\right)$

The value of the function will be maximum at,

$x=-\dfrac{b}{2a}$

Putting the values,

$x=-\dfrac{300}{2\times (-10)}=\dfrac{300}{2\times 10}=\dfrac{300}{20}=15$

So at x=15 or for 15 number of trees the production will be ,maximum.

Putting x=15 in f(x) will yield the maximum production of apples.

$P=40000+300(15)-10(15)^2=42,250$

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2 years ago

Analysis of an accident scene indicates a car was traveling at a velocity of 69.5 mph (31.1 m/s) along the positive x-axis at th

STatiana [176]

We can find the acceleration via

${v_f}^2-{v_i}^2=2a\Delta x$

We have

$\left(5.20\dfrac{\rm m}{\rm s}\right)^2-\left(31.1\dfrac{\rm m}{\rm s}\right)^2=2a(115\,\mathrm m)$

$\implies\boxed{a=-4.09\dfrac{\rm m}{\mathrm s^2}}$

Then by definition of average acceleration,

$a_{\rm ave}=\dfrac{v_f-v_i}t$

so that

$-4.09\dfrac{\rm m}{\mathrm s^2}=\dfrac{5.20\frac{\rm m}{\rm s}-31.1\frac{\rm m}{\rm s}}t$

$\implies\boxed{t=6.33\,\mathrm s}$

We alternatively could have found the time without knowing the acceleration. Since acceleration is constant, the average velocity is

$v_{\rm ave}=\dfrac{x_f-x_i}t=\dfrac{v_f+v_i}2$

Then

$\dfrac{115\,\rm m}t=\dfrac{5.20\frac{\rm m}{\rm s}+31.1\frac{\rm m}{\rm s}}2$

$\implies\boxed{t=6.33\,\mathrm s}$

7 0

2 years ago

The Oregon trail is 2.197 miles long. How long would it take a covered wagon travelling 20 miles a day to complete the trip? Wri

Bess [88]

Answer: It needs 2.4 hours to complete the trip.

Step-by-step explanation:

Since we have given that

Length of Oregon trail = 2.197 miles

Speed at which it travel = 20 miles per day

we need to find the time taken by it ,

As we know that

$Time=\frac{Distance}{Speed}$

$Time=\frac{2.197}{20}\\\\Time=0.10\text{ days}$

So,

it will be changed into hours

$1\text{ day}=24\text{ hours}\\\\0.1\text{ day}=24\times 0.1=2.4\text{ hours}$

so, it needs 2.4 hours to complete the trip.

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3 years ago