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nika2105 [10]
3 years ago
14

HELP PLEASE!!!!!!!!!!!!!!​

Mathematics
1 answer:
Genrish500 [490]3 years ago
6 0

Answer:

what

Step-by-step explanation:

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7-4+6=7 Complete the equation to make it equal
boyakko [2]

Answer:

7-4+6=7 + 2

Step-by-step explanation:

7 0
4 years ago
The midpoint of -7 and 8 on the number line is 1/2 true or false
Phoenix [80]

Answer:

True

Step-by-step explanation:

Yo find the midpoint between 2 points x1 and x2

midpoint = (x1+x2)/2

midpoint = (-7+8)/2

midpoint = 1/2

8 0
3 years ago
Is square root 1-cos^2 ø= -sin ø if so in which quadrant does angle O terminate
lapo4ka [179]

The Trigonometric Pythagorean Theorem is always true:

\cos^2 \theta + \sin ^2 \theta = 1

If we solve for \sin \theta we get

\sin ^2 \theta = 1 - \cos^2 \theta

We know

0 \le \cos ^2 \theta \le 1

0 \le \sin ^2 \theta \le 1

so both sides are clearly between zero and one.

It's actually much better to do geometry using squared sine, but that's a topic for another day. It comes from replacing angle, a complicated directed meeting of two rays, with the intersection of two lines. Among many advantages, this eliminates quadrants.

But we know sine and cosine can be positive or negative. So we need the multivalued square root:

\sin \theta =\pm \sqrt{  1 - \cos^2 \theta}

The \pm means that it might be plus, it might be minus, if you just tell me the cosine there's not (usually) enough information to know which.

So yes, sometimes

\sin \theta = - \sqrt{ 1- \cos^2 \theta}

That's a negative sine. If the cosine is positive, \theta is in the fourth quadrant. If the cosine is negative, \theta is in the third quadrant.

6 0
4 years ago
Please answer this question! 20 points and brainliest!
Svetllana [295]

Answer:

Subtraction, addition, division

Step-by-step explanation:

4 0
4 years ago
Answer this for me pls
cricket20 [7]

Answer:

\sqrt{10}

Step-by-step explanation:

Let the third side be x

Using Pythagoras' identity on the right triangle.

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

x² + 9² = (\sqrt{91})², that is

x² + 81 = 91 ( subtract 81 from both sides )

x² = 10 ( take the square root of both sides )

x = \sqrt{10}

6 0
3 years ago
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