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lyudmila [28]
4 years ago
5

Which one is right. I am lost and I need help

Mathematics
1 answer:
Lubov Fominskaja [6]4 years ago
8 0

Reflection across y=x is a special case transformation


(x,y) \rightarrow (y,x)


The original triangle has vertices A(-5,1), B(-4,3), C(-2,1), D(-3,-1) so the transformed triangle has vertices


A'(1,-5), B'(3,-4), C'(1,-2), D'(-1,-3)


Choice A'(1,-5)




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Answer:

1503.37

Step-by-step explanation:

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Use sets A and B to answer the question.
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A\cap B=\{2,4\}

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I need help for my hw asap!! Help pls!!! Thank you
djyliett [7]

Answer:

1. S.A. = 4350 cm²

2. S.A. = 864 cm²

3. S.A. = 240 cm²

4. S.A. = 224 m²

5. S.A. = 301.6 in.²

6. S.A. = 6,082.1 cm²

7. S.A. = 923.6 in.²

Step-by-step explanation:

1. Surface area of the rectangular prism = 2(LW + LH + WH)

L = 45 cm

W = 25 cm

H = 15 cm

S.A. = 2(45*25 + 45*15 + 25*15)

S.A. = 4350 m²

2. Surface area of the cube = 6a²

a = 12 cm

S.A. = 6(12²)

S.A. = 864 cm²

3. Surface area of triangular prism = bh + (s1 + s2 + s3)*H

b = 4 cm

h = 6 cm

s1 = 4 cm

s2 = 7 cm

s3 = 7 cm

H = 12 cm

Plug in the values

S.A. = 4*6 + (4 + 7 + 7)*12

S.A. = 24 + (18)*12

S.A. = 24 + 216

S.A. = 240 cm²

4. Surface area of the square based pyramid = area of the square base + 4(area of 1 triangular face)

S.A. = (8*8) + 4[(8*10)/2]

S.A. = 64 + 4(40)

S.A. = 64 + 160

S.A. = 224 cm²

5. Surface area of the cone = πrl + πr²

r = 6 in.

l = 10 in.

S.A. = π*6*10 + π*r²

S.A. = 60π + 36π

S.A. = 301.592895

S.A. = 301.6 in.² (nearest tenth)

6. Surface area of the sphere = 4πr²

r = 22 cm

S.A. = 4*π*22²

S.A. = 1,936π

S.A. = 6,082.1 cm² (nearest tenth)

7. Surface area of the cylinder = 2πrh + 2πr²

r = 7 in.

h = 14 in.

S.A. = 2*π*7*14 + 2*π*7²

S.A. = 923.6 in.² (nearest tenth)

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