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2 years ago

I need help with this what’s the answer

Mathematics

2 answers:

Vikentia [17]2 years ago

8 0

Twice the weight: 2x
2.5 pounds more: +2.5
2x + 2.5
The solution would be B

Dovator [93]2 years ago

7 0

Answer:

Step-by-step explanation:

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A railway engine starts shunting wagons by first going 1000m north of railway station. It reverses and travels 1250m and then it

Ainat [17]

Answer:

450m South

Step-by-step explanation:

Total distance traveled Northward :

1000m + 600m = 1600m Northward

Total distance traveled Southward :

1250m + 800m = 2050m

The Displacement :

Southward - Northward

2050m - 1650m

= 450m

Since, it covers more distance towards the south, then, direction is southward

450m South

8 0

2 years ago

4. Dean Pelton wants to perform calculations to impress the accreditation consultants, but upon asking for information about GPA

Leya [2.2K]

Answer:

the minimum records to be retrieved by using Chebysher - one sided inequality is 17.

Step-by-step explanation:

Let assume that n should represent the number of the students

SO, $\bar x$ can now be the sample mean of number of students in GPA's

To obtain n such that $P( \bar x \leq 2.3 ) \leq .04$

⇒ $P( \bar x \geq 2.3 ) \geq .96$

However ;

$E(x) = \int\limits^4_2 Dx (2+e^{-x} ) 4x = D \\ \\ = D(e^{-x} (e^xx^2 - x-1 ) ) ^D_2 = 12.314 D$

$E(x^2) = D\int\limits^4_2 (2+e^{-x})dx \\ \\ = \dfrac{D}{3}[e^{-4} (2e^x x^3 -3x^2 -6x -6)]^4__2}}= 38.21 \ D$

Similarly;

$D\int\limits^4_2(2+ e^{-x}) dx = 1$

⇒ $D*(2x-e^{-x} ) |^4_2 = 1$

⇒ $D*4.117 = 1$

⇒ $D= \dfrac{1}{4.117}$

$\mu = E(x) = 2.991013 ; \\ \\ E(x^2) = 9.28103$

∴ $Var (x) = E(x^2) - E^2(x) \\ \\ = .3348711$

Now; $P(\bar \geq 2.3) = P( \bar x - 2.991013 \geq 2.3 - 2.991013) \\ \\ = P( \omega \geq .691013) \ \ \ \ \ \ \ \ \ \ (x = E(\bar x ) - \mu)$

Using Chebysher one sided inequality ; we have:

$P(\omega \geq -.691013) \geq \dfrac{(.691013)^2}{Var ( \omega) +(.691013)^2}$

So; $(\omega = \bar x - \mu)$

⇒ $E(\omega ) = 0 \\ \\ Var (\omega ) = \dfrac{Var (x_i)}{n}$

∴ $P(\omega \geq .691013) \geq \dfrac{(.691013)^2}{\frac{.3348711}{n}+(691013)^2}$

To determine n; such that ;

$\dfrac{(.691013)^2}{\frac{.3348711}{n}+(691013)^2} \geq 0.96 \\ \\ \\ (.691013)^2(1-.96) \geq \dfrac{-3348711*.96}{n}$

⇒ $n \geq \dfrac{.3348711*.96}{.04*(.691013)^2}$

$n \geq 16.83125$

Thus; we can conclude that; the minimum records to be retrieved by using Chebysher - one sided inequality is 17.

5 0

2 years ago

G=b-ca <br><br> PLEASE HELP ! what is a ??

Nikitich [7]

G=b-ca
Subtract b from both sides
G-b=-ca
Divide by -c
(G-b)/-c=a

I hope this Helps!

8 0

2 years ago

There are 10 balloons in an arrangement and 7 of them are red. What percentage of red balloons are in the arrangement?

jok3333 [9.3K]

Answer:

70% are red.

Step-by-step explanation:

Divide this: 7 divided by 10 equals 0.7

0.7 is 70% in percent

Please give me brainliest

4 0

2 years ago

Is the relation { (5, 2), (-1, 6), (8, -2), (5, 3)} a function? why or why not? list the domain and range

Tasya [4]

Answer:

it is not a function because the input 5 (x) has more than one output (y)

domain (5,-1,8)

range (2,6,-2,3)

Step-by-step explanation:

5 0

3 years ago