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3 years ago

HELP? In the diagram, BC ∥ DE What is CE ? Enter your answer in the box.

Mathematics

2 answers:

galina1969 [7]3 years ago

4 0

Answer:

15 cm

Step-by-step explanation:

Thats what I put on my quiz, and got it( :

jekas [21]3 years ago

3 0

Since BC ∥ DE, we only apply thales theorem, it is

AB / AD = AC / AE, so we can find directly AE , AB / AD = AC / AE implies AB x AE = AC x AD and AC= AB x AE / AD= 12 x 3 /2=18
since AC= 18, and AC=AE+CE, so we can get CE= AC - AE=18-3=15
CE=15cm

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Is this right, can someone please explain so?

Orlov [11]

You have to turn them in to the lowest common denominator

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3 years ago

The scouts sold small and large boxes of cookies as a fund raiser. One scout sold 7 small boxes and 12 large boxes for $54.00. A

soldier1979 [14.2K]

Answer:

Step-by-step explanation:

A) When the first equation is multiplied by 5 and the second equation by –6 ,

the equations become,

35x + 60y=54

-30x - 60y=60

Hence we can eliminate y by adding the equation.

B) When the first equation is multiplied by -5 and the second equation by 6 ,

the equations become,

-35x - 60y=54

30x + 60y=60

Hence we can eliminate y by adding the equation.

C) When the first equation is multiplied by -5 and the second equation by 7,

the equations become,

-35x - 60y=54

35x - 70y=60

Hence we can eliminate x by adding the equation.

D) When the first equation is multiplied by 5 and the second equation by -7,

the equations become,

35x + 60y=54

-35x - 70y=60

Hence we can eliminate x by adding the equation.

E) When the first equation is multiplied by -5 and the second equation by 10,

the equations become,

-35x - 60y=54

50x - 100y=60

Hence we can not eliminate x by adding the equation.

5 0

3 years ago

Consider the following sets of sample data: A: $30,500, $27,500, $31,200, $24,000, $27,100, $28,600, $39,100, $36,900, $35,000,

Alecsey [184]

Answer:

$CV=0.2$ ---- dataset 1

$CV = 7.2$ --- dataset 2

Step-by-step explanation:

Given

$A: 30500, 27500, 31200, 24000, 27100,28600, 39100, 36900, 35000, 21400, 37900, 27900, 18700,$ $33100$

$B: 4.29, 4.88, 4.34, 4.17, 4.52, 4.80, 3.28, 3.79, 4.84, 4.77, 3.11$

Required

The coefficient of variation of each

Dataset A

Calculate the mean

$\mu = \frac{\sum x}{n}$

$\mu = \frac{30500+ 27500+31200+24000+ 27100+28600+ 39100+ 36900+ 35000+ 21400+ 37900+ 27900+ 18700+33100}{14}$ $\mu = \frac{418900}{14}$

$\mu = 29921.43$

Next, calculate the standard deviation using:

$\sigma = \sqrt{\frac{\sum(x - \mu)^2}{n}}$

So, we have:

$\sigma= \sqrt{\frac{(30500 - 29921.43)^2 +.................+ (18700- 29921.43)^2 + (33100- 29921.43)^2}{13}}$

$\sigma= \sqrt{\frac{487723571.42857}{14}}$

$\sigma= \sqrt{34837397.959184}$

$\sigma= 5902.32$

So, the coefficient of variation is:

$CV=\frac{\sigma}{\mu}$

$CV=\frac{5902.32}{29921.43}$

$CV=0.2$ --- approximated

Dataset B

Calculate the mean

$\mu = \frac{\sum x}{n}$

$\mu = \frac{4.29+ 4.88+ 4.34+ 4.17+ 4.52+ 4.80+ 3.28+ 3.79+ 4.84+ 4.77+ 3.11}{11}$

$\mu = \frac{46.79}{11}$

$\mu = 4.25$

Next, calculate the standard deviation using:

$\sigma = \sqrt{\frac{\sum(x - \mu)^2}{n}}$

$\sigma = \sqrt{\frac{(4.29 - 4.25)^2 + (4.88- 4.25)^2 +.........+ (3.11- 4.25)^2}{11}}$

$\sigma = \sqrt{\frac{3.859}{11}}$

$\sigma = \sqrt{0.35081818181}$

$\sigma = 0.593$

So, the coefficient of variation is:

$CV=\frac{\sigma}{\mu}$

$CV = \frac{4.25}{0.5903}$

$CV = 7.2$ -- approximated

3 0

3 years ago

a wooden box has external dimensions 40 cm by 34 cm by 30 cm. if the wood is 1 cm thick how many cm3 of wood is used in it ?

Westkost [7]

Answer:

6752 cm³ of wood

Step-by-step explanation:

V = 40cm×34cm×30cm = 40800 cm³

v = 38cm×32cm×28cm = 34048 cm³

V - v = 40800cm³ - 34048cm³ = 6752 cm³ of wood

7 0

3 years ago

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Estimated round up $6000 and divide by $30(rounded up) = $200 each estimated
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6 0

3 years ago

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