Remember SohCahToa
For this let's use sine.
SinA = opposite/adjacent
SinA = x/c
We know c = 8 and A = 21
Sin21 = x/8
x = (sin21)8
Put that in the calculator:
<h2>x = 2.87 (rounded) </h2><h2 />
hope this helps :D
Answer:
Step-by-step explanation:
given,
log₂ (800)
using logarithmic identity
logₐ a = 1
logₐ x³ = 3 logₐ x
log (ab) = log a + log b
logₐ x =
now,
log₂ (800)
log₂ (2³ × 100 )
log₂ (2³) + log₂ (100)
3 log₂ (2) + log₂ (10²)
3 + 2 log₂ (10)
2.1
If the number was 2.15, you would round to 2.2 because any place that is 5 or greater rounds up and any place less than 5 rounds down.
.1 is the tenths place
.11 is the one hundredths places
4(8-x)+36=102-6x
Expand by using distributive property
32 - 4x + 36 = 102 - 6x
Combine like terms
-4x + 68 = 102 - 6x
Add 6x to both sides
2x + 68 = 102
Subtract 68 from both sides
2x = 34
Divide both sides by 2
x = 17
Answer
x = 17
Answer:
If we forget about the £150 more for a second then we can think of some very basic scenarios where the 5 : 2 ratio is satisfied. For example, Jon has £5 Nik has £2 or Jon has £10 Nik has £4 and so on. From this information we can set up an equation to find what Nik has if Jon has say £100. What is that equation? we let J represent how much Jon has and N represent how much Nik has then we can say2J = 5N and this comes directly from the ratio given.Now we consider the £150 more that Jon gets and we can set up another equationJ = N + 150 if Nik got £150 more then they'd have the same.So now we have 2 equations and two variables and we can solve it like they're simultaneous equations. There are a couple of methods for solving simultaneous equations but in this case the method to use is obvious, substitution. We use substitution because our second equation J = N + 150 is already in terms of J so we can just substitute it in to the first equation. By doing this we get2(N + 150) = 5N now we expand the brackets2N + 300 = 5N take N on to one side300 = 3N make N the subjectN = 100 we have an equation to find what J is if N is 100, 2J = 5N2J = 5(100) make J the subjectJ = 250
Step-by-step explanation: