For this case we have the following quadratic equation:
Rewriting the equation we have:
From here, we have:
Substituting values in the quadratic equation we have:
Rewriting the equation we have:
Answer:
The values of x are given by:
The nearest litre should be 3
Answer:
A. = 20 in²
B. = 45 ft²
C. = 29.5 ft²
D. = 36 ft²
E. = 28 ft²
Step-by-step explanation:
A. Formula = A = (h_b b)/2 = base 10 ft height_b= 4ft = 20 ft²
B. We have a rectagnle and a triangle: Formula: A = lw
= A = 30 ft² and now the triangle with the same formula as above: A = 15 ft²
30 ft²+15 ft² = 45 ft²
C. we have 2 rectagnle and a triangle: First the small recangle: A= lw = A = 1ft x 2ft = 2ft²
Second rectangle: 5 ft x 4 ft = 20 ft²
Right angeled triangle Formula: (ab)/2 = 3 ft x 5 ft = 7.5 ft²
Add it all together: 2ft²+20ft²+7.5ft² = 29.5 ft²
D. is a rectangle and a triangle: 8 ft x 3 ft = 24ft²
the triangle 8 ft x 2ft = 12 ft²; add 24 ft²+12 ft² = 36ft²
E. is a right-angled triangle (see fromula above) = (14 ft x 4 ft)/2 = 28ft²
