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castortr0y [4]
3 years ago
11

More and more businesses and homeowners are installing solar panels on their roofs to draw energy from the sun's rays. According

to the U.S. Department of Energy, the solar cell kilowatt-hour use in the United States (in millions) is projected to be S(t) = 0.73t2 + 15.8t +2.7 (0 < t < 8) in year t, with t = 0 corresponding to 2000.
What was the number of projected solar cell kilowatt-hours used in the United States for 2001? For 2002?
Mathematics
1 answer:
4vir4ik [10]3 years ago
5 0

Answer:

S(2001) = 19.23

S(2002) = 37.22

Step-by-step explanation:

Given that;

S(t) = 0.73t^2 + 15.8t +2.7

t = 0 corresponding 2000

t = 1 then, its mean year 2001

so

S(2001) = 0.73(1)^2 + 15.8(1) +2.7

= 0.73 + 15.8 + 2.7

S(2001) = 19.23

also

t = 2 then, it means 2002

so

S(2002) = 0.73(2)^2 + 15.8(2) +2.7

= 2.92 + 31.6 + 2.7

S(2002) = 37.22

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Answer:

the answer of the GCF is 1

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1/4 + 1/2 +x=−3/4
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Work from the left to right.
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Which number is the common difference of the sequence -92,-74,-54,-38,-20?
Mkey [24]
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uysha [10]

Answer:

1) 0.0826052-2.776\frac{0.000013424}{\sqrt{5}}=0.082588    

0.0826052+2.776\frac{0.000013424}{\sqrt{5}}=0.0826219    

b) ME= 2.776\frac{0.000013424}{\sqrt{5}}=0.0000166653

And we want 2/3 of the margin of error so then would be: 2/3 ME = 0.00001111

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (1)

And on this case we have that ME =0.00001111016 and we are interested in order to find the value of n, if we solve n from equation (1) we got:

n=(\frac{z_{\alpha/2} s}{ME})^2   (2)

Replacing we got:

n=(\frac{2.776(0.000013424)}{0.00001111})^2 =11.25 \approx 12

So the answer for this case would be n=12 rounded up to the nearest integer

Step-by-step explanation:

Information given

0.082601, 0.082621, 0.082589, 0.082617, 0.082598

We can calculate the sample mean and deviation with the following formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

\bar X=0.0826052 represent the sample mean

\mu population mean

s=0.000013424 represent the sample standard deviation

n=5 represent the sample size  

Part 1

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The degrees of freedom, given by:

df=n-1=5-1=4

The Confidence level is 0.95 or 95%, and the significance would be \alpha=0.05 and \alpha/2 =0.025, the critical value would be using the t distribution with 4 degrees of freedom: t_{\alpha/2}=2.776

Now we have everything in order to replace into formula (1):

0.0826052-2.776\frac{0.000013424}{\sqrt{5}}=0.082588    

0.0826052+2.776\frac{0.000013424}{\sqrt{5}}=0.0826219    

Part 2

The original margin of error is given by:

ME= 2.776\frac{0.000013424}{\sqrt{5}}=0.0000166653

And we want 2/3 of the margin of error so then would be: 2/3 ME = 0.00001111

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (1)

And on this case we have that ME =0.00001111016 and we are interested in order to find the value of n, if we solve n from equation (1) we got:

n=(\frac{z_{\alpha/2} s}{ME})^2   (2)

Replacing we got:

n=(\frac{2.776(0.000013424)}{0.00001111})^2 =11.25 \approx 12

So the answer for this case would be n=12 rounded up to the nearest integer

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3 years ago
X2 + 4x - 9 = 5x + 3<br> O A. 4<br> O B. -3<br> O C. -7<br> O D. 5<br> E. -2<br> F-4
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Answer:

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2 years ago
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