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Pavlova-9 [17]
3 years ago
13

Which number is the common difference of the sequence -92,-74,-54,-38,-20?

Mathematics
2 answers:
Mkey [24]3 years ago
8 0
The common difference if there is one is the constant difference that occurs between any term and the term before it.... in this case:

There is no common difference, 

dx=18,20,16,18  the difference or velocity is not constant...

d2x=2, -4,2  the acceleration is not constant...

d3x=-6,6  the thrust is not constant  

Now we might be tempted to say that:

d4x=12 and say that that is constant and we COULD make a quartic equation fit all the data points, but without further data points in the sequence there is no mathematical proof that the quartic equation would produce accurate data points outside of the range given...

And solving a system of five equations for five unknowns is tedious for such a problem...a^4+bx^3+cx^2+dx+e=y

madam [21]3 years ago
8 0

Answer:

The answer is 18

Step-by-step explanation:

Each number is getting 18 added to it

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3 years ago
Could y’all help me out with this?
Aneli [31]

Answer:

M' (5,-1)

D' (5,1)

A' (3,4)

W' (4,-1)

Step-by-step explanation:

We want to find the coordinates of Quadrilateral MDAW with vertices M(-1, 5), D(1,5), A(4,3), and W(-1,4) after a reflection across y = x.

We can find these coordinates by following the following rule:

Reflection over y = x rule : ( x , y ) ---> ( y , x )

Explanation of rule: Simply swap the places of the x and y values.

Applying rule to given coordinates:

M(-1,5) -----> swap x and y values -----> M'(5,-1)

D(1,5) ----> swap x and y values -----> D'(5,1)

A(4,3) -----> swap x and y values -----> A'(3,4)

W(-1,4) -----> swap x and y values -----> W'(4,-1)

So the coordinates of Quadrilateral MDAW  after a reflection over the y = x  line are M'(5,-1) , D'(5,1) , A'(3,4) , W'(4,-1)

For more validation, refer to the attached image

4 0
2 years ago
What is another way to write the expression t. (14--5) ?
melomori [17]

Answer: Second option.

Step-by-step explanation:

It is important to remember the Distributive Property in order to solve this exercise.

The Distributive property states that:

a(b+c)=ab+ac\\\\\\a(b-c)=ab-ac

In this case you have the following expression provided in the exercise:

t(14-5)

Then, in order to write this expression in another way, you can apply the Distributive property. Multiply each number inside the parentheses by "t".

Applying this procedure, you get:

t(14-5)=(t14)-(t5)

Notice that this expression matches with the one shown in the the second option.

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Step-by-step explanation:

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