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Alexeev081 [22]
2 years ago
6

X+3y=0 9y=-3x how many solutions does this system have

Mathematics
1 answer:
kramer2 years ago
3 0
I only found 1 solution when x=0 and y=0. Otherwise, other rational numbers don’t work. However I’m not 100% sure.
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Fran naders insurance coverage bodily Injury 25/100 and $100,000 property damage. It has a $50-deductible comprehensive and a $5
vladimir2022 [97]

Answer:

$250,000

Step-by-step explanation:

This is the correct question below;

Fran naders insurance coverage bodily Injury 25/100 and $100,000 property damage. It has a $50-deductible comprehensive and a $50-deductible collision. Her car is in age group C and Insurance-rating group 10(or C,10) and her driver-rating Factor is 1.50.

Find her annual premium.

To calculate this, we proceed as follows;

Mathematically,

Annual premium = Face amount * $1000

25/100 * 100,000 * 100

This is 25,000 * 100 = $250,000

7 0
3 years ago
Read 2 more answers
Need help seriously
Dima020 [189]
It’s not hard bro you gotta lean probability it’s really easy
5 0
3 years ago
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Here a subtraction problem that has been solved incorrectly what is the right way 74-25=59​
jek_recluse [69]

Answer:

74-25 is 49

Step-by-step explanation:

7 0
2 years ago
Can anyone help me with this please
olga_2 [115]

Hi there!

\large\boxed{\frac{1}{4}, -\frac{3}{2}}

13y² + 10y - 3 = 5y²

Begin by moving all terms to one side:

13y² + 10y - 3 - 5y² = 0

Combine like terms:

8y² + 10y - 3 = 0

Factor using the guess-and-check method.

(4y - 1)(2y + 3) = 0

Set each factor equal to 0 to find the solutions:

4y - 1 = 0

4y = 1

y = 1/4

2y + 3 = 0

2y = -3

y = -3/2

8 0
2 years ago
Please help with this question
My name is Ann [436]

In a symmetric histogram, you have the same number of points to the left and to the right of the median. An example of this is the distribution {1,2,3,4,5}. We have 3 as the median and there are two items below the median (1,2) and two items above the median (4,5).

If we place another number into this distribution, say the number 5, then we have {1,2,3,4,5,5} and we no longer have symmetry. We can fix this by adding in 1 to get {1,1,2,3,4,5,5} and now we have symmetry again. Think of it like having a weight scale. If you add a coin on one side, then you have to add the same weight to the other side to keep balance.

4 0
2 years ago
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