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3 years ago

5x+2y= -11 and 2x+2y=5 solve using elimination

Mathematics

1 answer:

kifflom [539]3 years ago

8 0

Step-by-step explanation:

5x+2y=-11

2x+2y=5

so you find values that match or can multiply by something to match-2

5x+2y=-11

- 2x+2y=5

=3x+0y=-16

3x/3=-16/3

x=5 1/3

then substitute x in one of the equations to get y

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What are the intercepts of 2x + 3y – 6z = 30?

ycow [4]

Intercept of equation 2x + 3y - 6z = 30 is (15, 0, 0) , (0, 10, 0) and (0, 0, -5)

<h3><u>Solution:</u></h3>

Given equation is:

2x + 3y - 6z = 30

We have to find the intercepts

Intercept are the point where equations cut the x- axis, y- axis and z- axis.

y and z both are zero

So substitute y = 0 and z = 0 in given equation

2x + 3(0) - 6(0) = 30

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x = 15

<h3>Thus the intercept is (15, 0, 0)</h3>

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<h3>Thus the intercept is (0, 10, 0)</h3>

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So substitute x = 0 and y = 0 in given equation

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<h3>Thus the intercept is (0, 0, -5)</h3>

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3 years ago

Write an equation in slope-intercept form for the line that passes through (4,-3) and is parallel to the line described by y=1/2

Marat540 [252]

Given:

The point, (4, -3)

The line,

$y=\frac{1}{2}x+5$

To find an equation in slope-intercept form for the line that passes through (4,-3) and is parallel to the given line:

The slope of the line is,

$m=\frac{1}{2}$

Since the given line is parallel to the new line, so the slope will be same for the both.

Using the point-slope formula,

$y-y_1=m(x-x_1)$

Substitute the point and slope we get,

$\begin{gathered} y-(-3)=\frac{1}{2}(x-4) \\ y+3=\frac{1}{2}x-2 \\ y=\frac{1}{2}x-2-3 \\ y=\frac{1}{2}x-5 \end{gathered}$

Hence, the equation in slope-intercept form for the line is,

$y=\frac{1}{2}x-5$

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1 year ago

5x+2y= -11 and 2x+2y=5 solve using elimination​

5x+2y= -11 and 2x+2y=5 solve using elimination