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Yakvenalex [24]
3 years ago
7

One face of a cube has an area of 25cm.squared what is te surface area of the cube also what is the volume of this cube?

Mathematics
2 answers:
Andrew [12]3 years ago
6 0
25 * 6 = 150 is the surface area

The square root of 25 is 5, that's the length of each side

<span>5 * 5 * 5 = 125= volume

Did I help? Thank me by clicking Best Answer!
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xxTIMURxx [149]3 years ago
4 0
25*6=150= surface area
squar root of 25 is 5 so thats the lengh of each side
5*5*5=125= volume
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How do i solve 42 = -2d + 6
Mazyrski [523]
Substract 6 to both sides and you get 36 =-2d then you use the multiplicative inverse and d=-18.
8 0
3 years ago
Read 2 more answers
Simplify 3^2/3.3^1/5​
san4es73 [151]

ANSWER:

\frac{1}{5}  \\

EXPLANATION:

\frac{ \frac{{3}^{2}}{3 \times{3}^{1}}}{5}  =  \\

\frac{ \frac{9}{3 \times 3} }{5}  =  \\

\frac{ \frac{9}{9} }{5}  =  \\

\frac{1}{5}  \\

4 0
3 years ago
PLEASE ANSWER I WILL GIVE YOU BRAINIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
morpeh [17]

Answer:

C.

Step-by-step explanation:

y = 6x

if x = 1 , y = 6

if x = 2 , y = 12

if x = 3 , y = 18

if x = 4 , y = 24

4 0
3 years ago
Their sum is 6 and their difference is 36<br> Help plz
Ivan

Answer:

Step-by-step explanation:

if you can use negative numbers then   you could use 21 and -15

so

adding them together is  21 + (-15) = 6

and then subtracting  21 - (-15) =

                                     21 + 15 = 36

do you think that would work ?  :/

3 0
3 years ago
Read 2 more answers
How many complex zeros does the polynomial function have?<br> f(x)=−3x^6−2x^4+5x+6
REY [17]

one way would be to factor

I can't factor it so we will have to use Descartes' Rule of Signs which is helpful for finding how many real roots you have


it goes like this:

for a polynomial with real coefients, consider f(x)=-3x^6-2x^4+5x+6.

after arranging the terms in decending order in terms of degree, count how many times the signs of the coeffients change direction and minus 2 from that number until you get to 1 or 0. that will be the number of even roots the function can have

We have (-, -, +, +). the signs changed 1 times, so it has 1 real positive root


to get the negative roots, we evaluate f(-x) and see how many times the root changes

f(-x)=-3x^6-2x^4-5x+6

signs are (-, -, -, +). there was 1 change in sign

so the function has 1 real negative root



a total of 2 real roots


a function of degree n can have at most, n roots


our function is degree 6 so it has 6 roots

if 2 are real, then the others must be complex

6-2=4 so there are 4 complex roots


you can also show that there are only 2 real roots by using a graphing utility to see that there are only 2 real roots

7 0
3 years ago
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