Answer:
Math:9.75
Science:6
Step-by-step explanation:
Not 100% sure on those answers but here is hot to figure the problem out:
A point that falls outside the data set's inner fences is classified as a minor outlier, while one that falls outside the outer fences is classified as a major outlier. To find the inner fences for your data set, first, multiply the interquartile range by 1.5. Then, add the result to Q3 and subtract it from Q1.
<u>Answer:</u>
The correct answer option is P (S∩LC) = 0.16.
<u>Step-by-step explanation:</u>
It is known that the probability if someone is a smoker is P(S)=0.29 and the probability that someone has lung cancer, given that they are also smoker is P(LC|S)=0.552.
So using the above information, we are to find the probability hat a random person is a smoker and has lung cancer P(S∩LC).
P (LC|S) = P (S∩LC) / P (S)
Substituting the given values to get:
0.552 = P(S∩LC) / 0.29
P (S∩LC) = 0.552 × 0.29 = 0.16
Answer:
Area of triangle is 9.88 units^2
Step-by-step explanation:
We need to find the area of triangle
Given E(5,1), F(0,4), D(0,8)
We will use formula:
![Area\,\,of\,\,triangle =\sqrt{s(s-a)(s-b)s-c)} \\where\,\, s = \frac{a+b+c}{2}](https://tex.z-dn.net/?f=Area%5C%2C%5C%2Cof%5C%2C%5C%2Ctriangle%20%3D%5Csqrt%7Bs%28s-a%29%28s-b%29s-c%29%7D%20%5C%5Cwhere%5C%2C%5C%2C%20s%20%3D%20%5Cfrac%7Ba%2Bb%2Bc%7D%7B2%7D)
We need to find the lengths of side DE, EF and FD
Length of side DE = a = ![\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%28x_%7B2%7D-x_%7B1%7D%29%5E2%2B%28y_%7B2%7D-y_%7B1%7D%29%5E2%7D)
Length of side DE = a = ![=\sqrt{(5-0)^2+(1-8)^2}\\=\sqrt{(5)^2+(-7)^2}\\=\sqrt{25+49}\\=\sqrt{74}\\=8.60](https://tex.z-dn.net/?f=%3D%5Csqrt%7B%285-0%29%5E2%2B%281-8%29%5E2%7D%5C%5C%3D%5Csqrt%7B%285%29%5E2%2B%28-7%29%5E2%7D%5C%5C%3D%5Csqrt%7B25%2B49%7D%5C%5C%3D%5Csqrt%7B74%7D%5C%5C%3D8.60)
Length of side EF = b = ![\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%28x_%7B2%7D-x_%7B1%7D%29%5E2%2B%28y_%7B2%7D-y_%7B1%7D%29%5E2%7D)
Length of side EF = b = ![=\sqrt{(0-5)^2+(4-1)^2}\\=\sqrt{(-5)^2+(3)^2}\\=\sqrt{25+9}\\=\sqrt{34}\\=5.8](https://tex.z-dn.net/?f=%3D%5Csqrt%7B%280-5%29%5E2%2B%284-1%29%5E2%7D%5C%5C%3D%5Csqrt%7B%28-5%29%5E2%2B%283%29%5E2%7D%5C%5C%3D%5Csqrt%7B25%2B9%7D%5C%5C%3D%5Csqrt%7B34%7D%5C%5C%3D5.8)
Length of side FD = c = ![\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%28x_%7B2%7D-x_%7B1%7D%29%5E2%2B%28y_%7B2%7D-y_%7B1%7D%29%5E2%7D)
Length of side FD = c = ![=\sqrt{(0-0)^2+(8-4)^2}\\=\sqrt{(0)^2+(4)^2}\\=\sqrt{0+16}\\=\sqrt{16}\\=4](https://tex.z-dn.net/?f=%3D%5Csqrt%7B%280-0%29%5E2%2B%288-4%29%5E2%7D%5C%5C%3D%5Csqrt%7B%280%29%5E2%2B%284%29%5E2%7D%5C%5C%3D%5Csqrt%7B0%2B16%7D%5C%5C%3D%5Csqrt%7B16%7D%5C%5C%3D4)
so, a= 8.60, b= 5.8 and c = 4
s = a+b+c/2
s= 8.6+5.8+4/2
s= 9.2
Area of triangle=![=\sqrt{s(s-a)(s-b)s-c)}\\=\sqrt{9.2(9.2-8.6)(9.2-5.8)(9.2-4)}\\=\sqrt{9.2(0.6)(3.4)(5.2)}\\=\sqrt{97.5936}\\=9.88](https://tex.z-dn.net/?f=%3D%5Csqrt%7Bs%28s-a%29%28s-b%29s-c%29%7D%5C%5C%3D%5Csqrt%7B9.2%289.2-8.6%29%289.2-5.8%29%289.2-4%29%7D%5C%5C%3D%5Csqrt%7B9.2%280.6%29%283.4%29%285.2%29%7D%5C%5C%3D%5Csqrt%7B97.5936%7D%5C%5C%3D9.88)
So, area of triangle is 9.88 units^2
First we look for the area of the triangle which is given by:
A = (1/2) * (4) * (6)
A = 12 feet ^ 2
Area of the rectangles:
Rectangle 1:
R1 = (4) * (8)
R1 = 32 feet ^ 2
Rectangle 2:
R2 = (6) * (8)
R2 = 48 feet ^ 2
Rectangle 3:
R3 = (root (6 ^ 2 + 4 ^ 2)) * (8))
R3 = 57,68882041 feet ^ 2
The total area will be:
A = 2A + R1 + R2 + R3
Substituting values:
A = 2 * (12) + 32 + 48 + 57,68882041
A = 161.6888204 feet ^ 2
Answer:
The total area of the prism is:
A = 161.6888204 feet ^ 2