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3 years ago

What is the sum of the geometric sequence -4,24,-144, ... if there are 7 terms?

1 answer:

const2013 [10]3 years ago

4 0

$S_7=-4+24-144+864-5184+31104-186624$
$S_7=-4(1-6+36-216+1296-7776+46656)$
$(-6)S_7=-4(-6+36-216+1296-7776+46656-279936)$
$S_7-(-6)S_7=-4(1+279936)$
$S_7=-\dfrac47\times279937=-159964$

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What is meaning of rate?

Alja [10]

Answer:

1.a measure, quantity, or frequency, typically one measured against another quantity or measure.

Step-by-step explanation:

2.a fixed price paid or charged for something.

4 0

3 years ago

Read 2 more answers

Peter wants to test an assumption on the number of trees that tested positive for a particular infestation. He decides to focus

LUCKY_DIMON [66]

Answer:

H0 : P ≤ 0.12

H1 : P > 0.12

Step-by-step explanation:

12% = 12/ 100 = 0.12

Given the population proportion, P = 0.12

The claim is the alternative hypothesis, H1 ; which is to test if more than 12% of trees have been infested.

Hence, the alternative hypothesis will be ;

H1 : P > 0.12

The null hypothesis which is the initial truth is always the opposite of the alternative hypothesis, Therefore, we write our null as ;

The null hypothesis ; H0 : P ≤ 0.12

Therefore, we have :

H0 : P ≤ 0.12

H1 : P > 0.12

4 0

3 years ago

a family pass to the amusement park costs $54.using the distributive property , write an expression that can be used to find the

Mandarinka [93]

9 x 6 = 54 is this right I'll do distributive property next time

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3 years ago

Read 2 more answers

Lf R(x) = x2 – 3x – 1, find R(-2). a.9 b.-9 c.-3 d.-11

fenix001 [56]

Answer:

Step-by-step explanation:

If R(-2), then x = -2. Just plug in -2 for x. -2^2 - 3(-2) - 1 = 4 + 6 - 1 = 10 - 1 = 9. The answer is 9.

6 0

2 years ago

The slope of the line tangent to the curve y^2 + (xy+1)^3 = 0 at (2, -1) is ...?

Lina20 [59]

$\frac{d}{dx}(y^2 + (xy+1)^3 = 0)
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\\\frac{dy}{dx}2y + \left(\frac{d}{dx}(xy)+\frac{d}{dx}1\right)\ * 3(xy+1)^2 = 0
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\\\frac{dy}{dx}2y + \left(\frac{d}{dx}xy+x\frac{d}{dx}y+\frac{dx}{dx}\right)\ * 3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(\frac{dx}{dx}y+x\frac{dy}{dx}+\frac{dx}{dx}0\right)\ * 3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(y+x\frac{dy}{dx}\right)\ * 3(xy+1)^2 = 0$
$\frac{dy}{dx}2y + \left(y+x\frac{dy}{dx}\right)\ * 3(xy+1)^2 = 0
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\\\frac{dy}{dx}2y + \left(3y+3x\frac{dy}{dx}\right) (xy+1)^2 = 0
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\\2y\ y' + \left(3y+3x\ y'\right) (xy+1)^2 = 0
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\\2y\ y' + \left(3y+3x\ y'\right) ((xy)^2+2xy+1) = 0
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\\2y\ y' + \left(3y+3x\ y'\right) ((xy)^2+2xy+1) = 0
\\
\\2y\ y' + 3x^2y^3 +6xy^2+3y+(3x y' +6x^2y y'+3x^2y y') = 0
\\
\\3x^2y^3 +6xy^2+3y+(3x y' +6x^2y y'+3x^2y y'+2yy' ) = 0
\\
\\y'(3x +6x^2y+3x^2y+2y ) = -3x^2y^3 -6xy^2-3y

$
$y' = \frac{-3x^2y^3 -6xy^2-3y}{(3x +6x^2y+3x^2y+2y )};\ x=2,y=-1
\\
\\y' = \frac{-3(2)^2(-1)^3 -6(2)(-1)^2-3(-1)}{(3(2) +6(2)^2(-1)+3(2)^2(-1)+2(-1) )}
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\\y' = \frac{12 -12+3}{(6 -24-12-2 )}
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3 years ago