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ki77a [65]
3 years ago
14

Aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa

Mathematics
1 answer:
ki77a [65]3 years ago
8 0

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You need a 15% acid solution for a certain test, but your supplier only ships 5% solution and 17.5% solution. If you need 20 lit
Nimfa-mama [501]

Answer:

4 liters of 5% and 16 liters of 17.5%

Step-by-step explanation:

Let quantity of 5% be x liters and of 17.5% be y liters

x+y=20 hence y=20-x

Introducing percentages

0.05x+0.175(20-x)=0.15*20

0.05x+3.5-0.175x=3

-0.125x=-0.5

x=\frac {-0.5}{-0.125}=4

Therefore, y=20-x=20-4=16

You need 4 liters of 5% and 16 liters of 17.5% to achieve 20 liters of 15% acid solution

6 0
3 years ago
Read 2 more answers
Can somebody please help i need the help to help me pass my math class thx so much if you can
natulia [17]

Answer:

Step-by-step explanation:

1. x = 11.2

2. 13

3. 9

4. -7/15

5. 15b

6. -12x + 16

7. 4x + 4

8. 11x-10

9. 10a + 5

10. -x, 15, and 2b

Hope that helps, and good luck!

4 0
3 years ago
Z divided by 3-2z + 4(z-8) when z = 18 <br><br> A. -122<br> B. 6<br> C. -66<br> D. 10
murzikaleks [220]

Everywhere you see z, replace the letter with 18.

z/[(3- 2z)] + 4(z - 8)

18/[(3 - 2(18))] + 4(18 - 8)

You finish.

3 0
3 years ago
Mrs. Myles gave the same test to both her first and third period class. In first period, the median was 75 and the range was 30.
dolphi86 [110]
<span>D) There is not enough information to know if any of these is true.</span>
7 0
3 years ago
A 2-card hand is drawn from a standard deck of 52 cards. find the probability that the hand contains the given cards. two of the
ivann1987 [24]
This probability is the same as 1-(two different suited cards). Your first card can be any of the 52 cards. Your second card must be any of the 39 different suited remaining 51 cards. So the answer is 1 - (52/52)(39-51). Note: I assumed there was no replacement.
5 0
3 years ago
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